What is the domain and range of the function below?

If Benito earns $187.50 for 12.5 hours of work, how many hours must he work to earn $465.00?

jasenka [17]

$\bf \begin{array}{cclll}
amount&hours\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
187.50&12.5\\
465&x
\end{array}\implies \cfrac{187.50}{465}=\cfrac{12.5}{x}$

solve for "x"

6 0

4 years ago

Help!! Will give brainliest and bonus air-hugs!!

natali 33 [55]

Answer:

Step-by-step explanation:

A) either radius or diameter and height

V = πR²h or πD²h/4

B) Radius is half a diameter, R = 4 cm

C) Rather depends on how they are put together.

Placing the rectangular faces touching would make a cylinder

D) V = 3.14(4²)(2) = 100.48 ≈ 100 cm³

E) divide by 2

i.e. V = ½πR²h

F V = ½(3.14)(4²)(2) = 50.24 ≈ 50 cm³

4 0

3 years ago

If the answer is in square feet, the formula used could have been...

Blizzard [7]

Answer:

lxwxh

Step-by-step explanation:

6 0

3 years ago

James and Cameron are watching a film. They pause it with one fifth left to watch. What is the ratio of how much they have watch

goldenfox [79]

Answer:

The ratio of how much they have watched to how much they have left to see is 4 : 1.

Step-by-step explanation:

Consider that the total duration of the film is, 1.

It is provided that James and Cameron paused when there is one-fifth left to watch.

That is, they have already watched, $1-\frac{1}{5}=\frac{4}{5}$ th of the film.

Compute the ratio of how much they have watched to how much they have left to see as follows:

$\frac{\text{Duration Watched}}{\text{Duration Left}}=\frac{4/5}{1/5}=\frac{4}{1}=4:1$

Thus, the ratio of how much they have watched to how much they have left to see is 4 : 1.

5 0

3 years ago

Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa

Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

Let p = proportion of the students who are in favor of Mike.

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, $H_A$ : p > 50% {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students body in favor of Mike = $\frac{55}{100}$ = 0.55

n = sample of students taken = 100

So, test statistics = $\frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }$

= 1.01

The value of z test statistics is 1.01.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

4 0

3 years ago