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Nana76 [90]
3 years ago
5

What is the surface area of the cube with the given edge length, s? Drag and drop the surface area into the box to match the edg

e length. s = 2.3 cm 13.8 cm²31.74 cm²132.65 cm²148.04 cm²
Mathematics
2 answers:
Elodia [21]3 years ago
8 0

For this case we have that by definition the surface area of the cube is given by:

A = 6s ^ 2

Where,

  • <em>s: is the side of the cube </em>

In this case we have that the side of the cube is given by:

s = 2.3 cm

Therefore, replacing values we have:

A = 6 (2.3) ^ 2\\A = 31.74 cm ^ 2

Answer:

The surface area of the cube is given by:

A = 31.74 cm ^ 2

Option 2

TEA [102]3 years ago
4 0
Cube surface area = side^2 * 6
cube surface area = 2.3^2 * 6
cube surface area = 31.74 cm^2


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A triangular pane of glass has a height of 30 inches and an area of 270 square inches. what is the length of the base pane
Tems11 [23]
The equation for the area of a triangle is A= b*h /2. So, plug in your known variables, and you get 270in^2= b*30 /2. First you multiply by 2 to cancel out the division for 2, which gets you 540= b* 30. To get "b" by itself, divide both sides by 30, giving you <u>18=b</u>.

To check this, plug in your new known variable, as 270= 18* 30 /2. This will equal as 270=270, confirming 18in as the correct measurement.
3 0
3 years ago
Please help!! Very urgent..thank you!!
erastova [34]

Answer : 4 times

Here it's given that ,

  • The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .

And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .

Let us take ,

  • base of blue butterfly be b
  • height of blue butterfly be h
  • Area be A .

Then ,

  • base of red butterfly will be 2b .
  • height of red butterfly will be 2h .
  • Area be A' .

We know that ,

→ area of the triangle = 1/2 × base × height

So that ,

→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)

→ A/A' = bh/4bh

→ A/A' = 1/4

→ A' = 4A

<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>

I hope this helps.

6 0
2 years ago
M² + 18m - 81 help me please ​
Marina CMI [18]
The question is incomplete
7 0
3 years ago
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
Ben has 3 times as many guppies as goldfish if he has a total of 20 fish how many guppies does have?
kondor19780726 [428]
Guppies: u
Goldfish: o

3 times as many guppies as goldfish
3*o = u   (there are more guppies than goldfish)

o + u = 20
o = 20 - u

Substitute in (20 - u)  for o in the first equation and solve:
3* (20 - u) = u
60 - 3u = u
60 = 4u
u  = 15

He has 15 guppies. Then substitute in the number of guppies into either equation to find the number of goldfish:
o + u = 20
o + (15) = 20
o = 5

Hope this helps! :)

4 0
3 years ago
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