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Nana76 [90]
3 years ago
5

What is the surface area of the cube with the given edge length, s? Drag and drop the surface area into the box to match the edg

e length. s = 2.3 cm 13.8 cm²31.74 cm²132.65 cm²148.04 cm²
Mathematics
2 answers:
Elodia [21]3 years ago
8 0

For this case we have that by definition the surface area of the cube is given by:

A = 6s ^ 2

Where,

  • <em>s: is the side of the cube </em>

In this case we have that the side of the cube is given by:

s = 2.3 cm

Therefore, replacing values we have:

A = 6 (2.3) ^ 2\\A = 31.74 cm ^ 2

Answer:

The surface area of the cube is given by:

A = 31.74 cm ^ 2

Option 2

TEA [102]3 years ago
4 0
Cube surface area = side^2 * 6
cube surface area = 2.3^2 * 6
cube surface area = 31.74 cm^2


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Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

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On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

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