Answer:
Sarah is incorrect.
Step-by-step explanation:
By plugging 10 in as 'x' to the equation, we get y=21+(2*10). 2 x 10 is 20, and 20 + 21 is <em>not</em> 42 - it's 41. So, Sarah is incorrect.
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
There is no graph I’m sorry I can’t help
Answer:
the slope is 4/3
Step-by-step explanation:
use the formula:
m=
where x1 and y1 can be any point and x2 and y2 can be any point.
I used the last relation as my x1,y1 and second last relation as my x2,y2 because it is easier to subtract them.
which is 8/6 or 4/3
Step-by-step explanation:
line s || line t
r is the transversal,
Therefore,
(7x-2)°= (6x+18)° {exterior alternate angles}
7x-6x=18+2
x=20°
r is also a straight line,
therefore,
7x-2+angle1=180° (straight angle)
7x-2+ angle1=180°
7(20)-2+ angle 1= 180°
140°-2+ angle 1= 180°
angle 1= (180-140+2 )°= 42°
angle 1= 42°
