Answer:
probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively
Step-by-step explanation:
assuming that there are no other contractors then:
probability that 1 , 2 or 3 win = 1
denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have
probability that 1 , 2 or 3 win = 1
probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1
2*P(X) + 3*P(X) + P(X) = 1
6*P(X) = 1
P(X) =1/6
then
-probability that contractor 1 wins = 2/6 (33%)
-probability that contractor 3 wins = 3/6 (50%)
-probability that contractor 3 wins = 1/6 (17%)
