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3 years ago

Please can someone help? As i'm not confident this is right for factorising 4b^2 + 8b + 3

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

5 0

Answer:

your answer is correct

Step-by-step explanation:

4b² + 8b + 3

Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term.

product = 4 × 3 = 12 and sum = + 8

The factors are 2 and 6

Use these factors to split the b- term

4b² + 2b + 6b + 3 ( factor the first/second and third/fourth terms )

= 2b(2b + 1) + 3(2b + 1) ← factor out (2b + 1) from each term

= (2b + 1)(2b + 3)

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3 years ago

Please can someone help? As i'm not confident this is right for factorising 4b^2 + 8b + 3 ​

Please can someone help? As i'm not confident this is right for factorising 4b^2 + 8b + 3