Please can someone help? As i'm not confident this is right for factorising 4b^2 + 8b + 3
1 answer:
Answer:
your answer is correct
Step-by-step explanation:
4b² + 8b + 3
Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term.
product = 4 × 3 = 12 and sum = + 8
The factors are 2 and 6
Use these factors to split the b- term
4b² + 2b + 6b + 3 ( factor the first/second and third/fourth terms )
= 2b(2b + 1) + 3(2b + 1) ← factor out (2b + 1) from each term
= (2b + 1)(2b + 3)
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