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Zina [86]
3 years ago
5

Simplify the expression

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0
For this problem I got 1125 but I think I mis read the way you wrote the problem
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The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3
Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is 258.75\ in^3.

Given:

Length = Height - 4 = h - 4

Width = 3 in

We need to find the height of the box.

Solution:

We know that the volume of the box.

Volume = Length\times height\times width

Substitute all given value in above formula.

258.75 = (h-4)\times h\times 3

Rewrite the equation as:

258.75 = 3h(h-4)

258.75 = 3h^2-12h

3h^2-12h-258.75=0

whole equation divided by 3.

h^2-4h-86.25=0

Use quadratic formula with a = 1, b = -4,c=-86.25

h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}

Put these a, b and c value in above equation.

h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}

h=\frac{4\pm \sqrt{16+345}}{2}

h=\frac{4\pm \sqrt{361}}{2}

h=\frac{4\pm 19}{2}

For positive sign

h=\frac{23}{2}  

h = 11.5 in

For negative sign

h=\frac{-15}{2}

h = -7.5

We take positive value of h.

Therefore, the height of the box h = 11.5 in

4 0
3 years ago
Between what two integers does 98 fall between
Nat2105 [25]

Answer: 99 and 97


Step-by-step explanation: If you make a numberline and write the numbers 90 through 100. 98 is in between integers 99 and 97.


8 0
3 years ago
Please help( I will give brainliest) <br><br> Thanks
Katen [24]

Answer:

i think it's c.

Step-by-step explanation:

sorry if this is wrong

5 0
3 years ago
Jana is on a two-day hike. The function graphed shows the total distance she hiked, in miles, after x hours on the second day.
evablogger [386]
Just took the same quiz.

The slope is 2.
The slope represents <span>the number of miles hiked every hour.</span>
4 0
4 years ago
Read 2 more answers
A function f is defined by f:x=3-2sinx for 0
Gala2k [10]
       f(x) = 3 - 2sin(x)
          0 = 3 - 2sin(x)
        - 3  - 3
         -3 = -2sin(x)
         -2        -2
        1¹/₂ = sin(x)
sin⁻¹(1¹/₂) = sin⁻¹[sin(x)]
sin⁻¹(1¹/₂) = x
5 0
3 years ago
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