All categories

3 years ago

Can someone please help me? I don't understand question d.

Mathematics

1 answer:

Sedaia [141]3 years ago

3 0

Answer:

Step-by-step explanation:

From the previous answers you know the angles and side lengths of the triangle:

α = 60°

Ф = 30°

and the side lengths:

1,2 and √3.

Remember:

sin = opposite / hypotenuse

cos = adjacent / hypotenuse

tan = opposite / adjacent

Now you can read off from the triangle:

sin 30° = 1/2

cos 60° = 1/2

sin 60° = √3/2

cos 30° = √3/2

tan 30° = 1/√3

tan 60° = √3

You might be interested in

Calculate the average rate of change over the intervals [0, 20] and [60, 80]. What does the average rate on these intervals tell

Assoli18 [71]

$\frac{20 - 80}{0 - 60 } = slope \: or the \: rate \: of \: \\ change \: \\ \\ \frac{ - 60}{ - 60} = 1$
It tells you that over these intervals the balloon is going at a constant speed.

4 0

3 years ago

Drag and drop the numbers into the boxes to create an expression that is equivalent to the given expression. b+b+b+b+4c−2b−c

Marat540 [252]

Answer:

I know this is late, but for<em> future people</em>:

I believe the answer is <u>2b+3c</u>.

Step-by-step explanation:

I'm pretty sure all you have to do is combine like terms.

I'm also taking the test at the moment.

3 0

3 years ago

Read 2 more answers

A bike rider is traveling at a speed of 15 feet per second. Write an expression for the distance the rider has traveled after s

bija089 [108]

distance = speed x time

distance time

45 ft 3.0 s

87 ft 5.8 s

166.5 ft 11.1 s

210 ft 14.0 s

4 0

3 years ago

The figure shows three exterior angles of triangle ABC. Show that the measure of angle 1 plus the measure of angle 2 plus the me

ivolga24 [154]

Step-by-step explanation:

Let the angle near point A be $A$ .

Let the angle near point B be $B$ .

Let the angle near point C be $C$ .

Let the external angle near point A be $extA$ .

Let the external angle near point B be $extB$ .

Let the external angle near point C be $extC$ .

According to exterior angle property,exterior angle of an angle is the sum of other two angles.

So,

$extA=B+C\\extB=A+C\\extC=A+B$

According to angle sum property,the sum of angles in the triangle add to $180$

$extA+extB+extC=B+C+A+C+A+B=2(A+B+C)=2\times 180=360^{0}$

3 0

3 years ago

Read 2 more answers

Ms. Larson was driving home from a vacation. At noon, she was 120 miles from home. Half an hour later, she was 98 miles from hom

melomori [17]

Answer: her speed was “44 miles per hour”

5 0

3 years ago