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3 years ago

A baker uses 2/3 of canister flour to bake 4 loaves how much flour does the baker need to make 3 loaves

Mathematics

1 answer:

fiasKO [112]3 years ago

8 0

Answer:

18.18

Step-by-step explanation:

1 loaf = 6.06

3 loaf = 18.18

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Convert 3.29 to a reduced fraction.

NNADVOKAT [17]

Answer: 329/100

Step-by-step explanation:

4 0

3 years ago

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What is the slope of a line perpendicular to the line y = −14x – 1?

mash [69]

Answer:

Step-by-step explanation:

y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = -14x - 1 ⇒ m₁ = -14

-14×m₂ = -1 ⇒ m₂ = ¹/₁₄

So, the slope of a line perpendicular to the line y = -14x - 1 is m = ¹/₁₄

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3 years ago

45 620 000 to the nearest million

aniked [119]

Answer:

46,000,000 (46 million)

Step-by-step explanation:

If the number to the right (in this case the hundred thousands place) is 5 or greater then you round up.

If it was lower than 5 you would round down.

As the number in the hundred thousands place is 6, this means we can round up.

6 0

3 years ago

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A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

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3 years ago

How is the solution

navik [9.2K]

Answer:

wdym what solution put the equation down so I can answer it 4 u

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3 years ago

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