He has 9 choices for the first role, and that leaves him 8 people to choose for the second so he has 9*8 = 72 choices for the first two roles; that leaves 7 possible choices for the third role so that gives him 9*8*7 choices or 504 different ways he can assign the roles. i think this is correct.
Answer:
The answer is C
Step-by-step explanation:
There are 3 y's and there are three z's
3(y+z) means that you are multiplying 3 and y, and 3 and z which gives you 3y+3y
Which also equals y+y+y+3z
Answer:
False.
Step-by-step explanation: