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Allushta [10]
4 years ago
7

Find (f+g)(x) if f(x)=5x-2 and g(x)=2x+1 A. 7x-1 B. 7x-3 C. 3x-1 D. 4x-3

Mathematics
2 answers:
guajiro [1.7K]4 years ago
5 0
This is an addition problem.

Rearrange the given equations as

<span>+ f(x)=5x-2 
+g(x)=2x+1
----------------
Add up each column, as follows:  (f+g)(x) = 7x - 1   (answer)</span>
Simora [160]4 years ago
5 0
7x-1 is the correct answer
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Solve using substitution method x-y=11;3x+10y=-6<br> explain please
Tatiana [17]
Ok so for starters you want to choose an equation and solve for a variable.
So, I am going to choose x from the first equation.
Add y to both sides and you get x=11+y
Next, substitute 11+y for x in the other equation so you get...
2(11+y) +10y=-6
Next distribute the 2 throug the 11 and the y
22+2y+10y=-6
12y=-28
y=-28/12
reduce this fraction to make this easier.
y=-7/3
Now plug in why to either of the equations to find x
x-(-7/3)=11
x+7/3=11
x=11-(7/3)
x=(33/3)-(7/3)
x=26/3
so x = 26/3 and y = -7/3
you can also check to see if this is correct by substituting each of these values into the equations.
6 0
3 years ago
Point A, located at (-2, 4), is translated down 6 units. What are the coordinates of A'?
lara [203]
(-8, 4)                             hope that helps

3 0
3 years ago
Read 2 more answers
The formula to find the surface area of a sphere is to take the radius of the sphere and square it and multiply that amount by p
yawa3891 [41]
500=4πr^2. first divide 500 from four which will equal 125, then divide 125 with π and it will equal 39.788 . finally √39.788. the answer will be r=6.3 or 6
8 0
3 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

7 0
3 years ago
Can someone answer this for me.
Marina CMI [18]

Answer:

A)  slope is 2/5 (positive slope)

B) slope is -2/6 (negative slope)

C) Yes, with different points, the slope remains the same.

3 0
3 years ago
Read 2 more answers
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