The domain is all of the possible x values, and there are none less than -3 in this case, so the answer is B, which shows that x must be greater than or equal to -3.
It has a minimum value at x = 3 and f(x) = 4
Vertex form is
f(x) = a(x - 3)^2 + 4 where a is some constant to be found
From the graph when x = 5 f(x) = 15, so
15 = a * 2^2 + 4
a = 15-4/4 = 11/4
so our equation is f(x) = 11/4(x - 3)^2 + 4
Each term is increasing by *3
Next three terms:
6, 18, 54
Answer:
Option D
Step-by-step explanation:
Given
Required
Determine if the function is quadratic
Start by representing the function as an x-y table
x:- 5 || 7 || 9 || 11
y:- 7 || 11 || 14 || 18
Next; Calculate the difference between the values of y
<em>The resulting difference are: 4 || 3 || 4</em>
Next; Calculate the difference between the difference of values of y
<em>The resulting difference are: -1 || 1</em>
<em>For the function to be quadratic, the above difference must be the same and since they are not, then the function does not represent a quadratic function.</em>
<em>Option D answers the question</em>
Y=-3/4x-6.5 you needed to plug in the given point into the y=mx+b formula.