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2 years ago

If you can solve, i will give brainliest!

Mathematics

1 answer:

Nutka1998 [239]2 years ago

7 0

Answer:

(2 + StartRoot 3 EndRoot) – (1 + StartRoot 3 EndRoot)i

Step-by-step explanation:

I'm 100% sure! ^^

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I need help on .5 and .6

Dovator [93]

5. 44 (forty four)
6. 58

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3 years ago

What are the solutions to the equation -5x2 + 3x = -9

Aleks04 [339]

Answer: Move terms to the left side−52+3=−9−5x2+3x=−9−52+3−(−9)=0−

Common factor−52+3+9=0−5x2+3x+9=0−(52−3−9)=0

Divide both sides by the same factor−(52−3−9)=0−(5x2−3x−9)=052−3−9=0

Solution=3±321 over 10

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat

Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : $v=\frac{distance}{time}$ . Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

$v\,*\,24\,min=d_A$

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

$v\,*\,32\,min=d_A+5\,miles$

Now we solve for $d_A$ in this last equation and make the substitution in the equation for car A:

$v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}$

So this is the speed of both cars: 0.625 miles/minute

3 0

3 years ago

PLEASE HELPPP ASAPP!! Combine and simplify the following radical expression.

Greeley [361]

After demonstrating the procedure by algebraic means, the expression $(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ is equivalent to $6\cdot \sqrt[3]{24}$ .

In this question we proceed to simplify $(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ by algebraic means into a single radical expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:

$(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ Given.
$(2\cdot 3) \cdot (\sqrt[3]{12} \cdot \sqrt[3]{2} )$ Commutative property/ Associative property.
$6\cdot \sqrt[3]{24}$ Definition of cubic root/ $\sqrt[n]{a} = \sqrt[n]{b}$ /Result

After demonstrating the procedure by algebraic means, the expression $(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ is equivalent to $6\cdot \sqrt[3]{24}$ .

To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591

7 0

2 years ago

Write an equation of the line passing through the points (−5, 6), (−7, 3)

blsea [12.9K]

Answer:

all work is shown and pictured

7 0

4 years ago