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nekit [7.7K]
3 years ago
6

Question 5 (1 point) What is the mean of this set of data: 78, 79, 80, 80, 89, 89, 92, 93, 94, 95, 95, 95 Round your answer to t

he nearest tenth.
88.3
89.4
92.1
88.6​
Mathematics
1 answer:
Len [333]3 years ago
7 0
88.3

add all the numbers, you get 1,059 and divide that by how many numbers there are which is 12 and you get 88.3
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7 0
4 years ago
Una recta con pendiente -2 ´pasa por el punto P(5, -1). La abscisa del punto Q que está en esa recta es 1. Encuentre la ordenada
oksian1 [2.3K]

Answer:

La ordenada de Q es 7.

Step-by-step explanation:

La ecuación de una recta es:

y = a*x + b

donde a es la pendiente y b es la ordenada al origen.

Para este problema, sabemos que la pendiente es -2

Entonces:

a = -2

y = -2*x + b

También sabemos que esta recta pasa por el punto (5, -1)

Esto significa que cuando evaluamos la ecuación en x = 5, y toma el valor y = -1

Si reemplazamos esos valores en la ecuación, obtenemos:

-1 = -2*5 + b

-1 = -10 + b

-1 + 10 = b

9 = b

Entonces la ecuación de la recta es:

y = -2*x + 9

Sabemos que el punto Q está en la línea, y la abscisa de este punto es 1.

Entonces este punto es Q (1, k)

donde k es la ordenada de este punto.

Porque nuestra línea también pasa por este punto, podemos concluir que cuando x = 1, y = k

Reemplazando eso en la ecuación tenemos:

k = -2*1 + 9 = -2 + 9 = 7

k = 7

La ordenada de Q es 7.

7 0
3 years ago
For the geometric sequence of a1=2 and r=2 find a5
Brrunno [24]

Answer:

a_5 = 32

Step-by-step explanation:

The nth term for the geometric sequence is given by:

a_n = a_1 \cdot r^{n-1}

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a_1 is the first term

r is the common ratio

n is the number of terms.

As per the statement:

For the geometric sequence of a_1=2 and r=2

We have to find a_5

for n = 5;

a_5=a_1 \cdot r^{n-1}

Substitute the given values we have;

a_5 = 2 \cdot 2^4 = 2 \cdot 16

⇒a_5 = 32

Therefore, the value of a_5 is, 32

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