A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
you would multiply the price by .20
Step-by-step explanation:
example:
20% of $160
sale, 20% off
160 x .20 = 32
$32 is 20% of $160, $128 is the sale price
Answer:
6 cm
Step-by-step explanation:
If you use Tangent-secant product (chapter reference), AB/AC = AD/AB so 4/2 = AD/4. AD = 8, CD = AD - AC = 8 - 2 = 6 cm.
Answer:
f(-5)=-5
Step-by-step explanation:
f(-5)= -((-2)(-5)-5)
= -(10-5)
= -(5)
= -5
1. <span>true
example:
2+3=3+2
5=5
2. </span><span>true
</span>example:
3*4=4*3
12=12
<span>
3. false
</span>example:
6-3=3-6
3≠-3
<span>
4. </span><span>true
</span>example:
(4 + 3) + 2= 4 + (3 + 2)
7 + 2 = 4 + 5
9 = 9
<span>
5. false
</span>example:<span>
(9 - 6) - 3 = 9 - (6 - 3)
</span>3 - 3 = 9 - 3
0 ≠ 6
6. true
example:
<span>2(3+4)= 2*3+2*4
2 * 7 = 6 + 8
14 = 14</span>
