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ikadub [295]
2 years ago
7

7. The length of a rectangle is 12 in. and the perimeter is 56 in. Find the width of the rectangle. A. 22 in. B. 16 in. C. 32 in

. D. 21 in
Mathematics
1 answer:
Eduardwww [97]2 years ago
5 0
I believe the answer would be b. I think this is because you know that the perimeter is the length times 2 and the width times 2 added together. If you do 12 times 2 you get 24. Then you subtract this from 56 because 56 is the perimeter of the whole thing. Then after this you get 32.Then divide 32 by 2 to find ONE of the widths.
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Option B: 4.0 cm is the value of w

Explanation:

It is given that \angle W= 39, \angle U=31, VW=3.3 and UV=w

Using the law of sines, we have,

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Substituting the values, we have,

\frac{\sin 31}{3.3}=\frac{\sin 39}{w}

Cross multiplying, we get,

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Simplifying, we have,

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Dividing both sides by 0.515, we have,

w=4.0

Thus, the value of w is 4.0 cm

Hence, Option B is the correct answer.

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