Ask question

Ask question

All categories

4 years ago

9

A bead necklace uses beads whose diameter, d, ranges from 5 millimeters to 8 millimeters (inclusive). The number of beads in a n

ecklace, n, is less than 300.
a. write an inequality describing the diameter of the beads.
b. write an inequality describing the number of beads

1 answer:

wolverine [178]4 years ago

4 0

The Answer is B Cause if u describe the number of beads u will get a correct answer
Hope this Halps :D

You might be interested in

You order an appetizer for $9.99, 2 entrées for $7.99 each, and a dessert for $3.49. The sales tax is 6% and you leave a 15% tip

Lemur [1.5K]

the total of the meal costs $29.46

the sales tax is $1.77

the tip is $4.69

so the total cost is $35.92

3 0

3 years ago

Solve for k.<br><br> 12k − 4k = 8

egoroff_w [7]

K=1

Hope this Helps

-Dante

6 0

3 years ago

Read 2 more answers

What are five number pairs that solve the equation vw=0 ?

prohojiy [21]

The following pairs all solve the equation [ v w = 0 ] :

1 and 0
2 and 0
3 and 0
4 and 0
0 and 5
0 and 6
0 and 7
0 and 8
1 million and 0

3 0

3 years ago

Find a quadratic function with the given x-values as the only two REAL zeros. x=-2 and x=8. Please show work! Will mark Brainlie

posledela

f(x) = (x- zero) * (x -zero)

f(x) = (x--2) (x-8)

f(x) = (x+2) (x-8)

if you need it multiplied out

f(x) = x^2 +2x -8x-16

f(x) = x^2 -6x-16

3 0

3 years ago

A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),

lana [24]

Answer:

(9) $\frac{1}{12}$ (10) $\frac{1}{12}$ (11) $\frac{5}{12}$ (12) $\frac{1}{4}$ (13) $\frac{1}{6}$ 14) $\frac{5}{36}$ (15) $\frac{1}{12}$ (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are: (3, 6), (4, 5), (5, 4)

$P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}$

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are: (1, 3),(2, 2),(3, 1),

$P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}$

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (4, 1), (4, 2), (5, 1)

$P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}$

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

$P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}$

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4), (5, 5), (6, 6)

$P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}$

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

$P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}$

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

$P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}$

16.Probability of getting two numbers with a sum of 14.

$P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0$

4 0

4 years ago