Answer:
26*26*26 = 17576 ways to select 3 letters
10*10= 100 ways to select 2 numbers
So then the total number of ways are:
possible ways
Step-by-step explanation:
For this case we assume that we have 26 letters from A to Z and 10 numbers from 0 to 9 .
And we want to calculate the number of possible passwords possible if the password consists of 3 letters followed by 2 digits.
And for this case we can use the multiplication principle of combinatories, since we don't have any restriction about the letters of the numbers we can have repetition of letters or numbers.
For the number of possible letters:
26*26*26 = 17576 ways to select 3 letters
10*10= 100 ways to select 2 numbers
So then the total number of ways are:
possible ways
z = 3m - 2n
Step-by-step explanation:
1000^m ÷ 100^n
Rewrite them in exponent form
That's
10^3m ÷ 10^2n
Since the bases are the same and they are dividing we subtract the exponents
That's
10^3m - 2n
Comparing it with 10^z
10^3m - 2n = 10^z
z = 3m - 2n
Hope this helps you
Answer:
the answer is 59048
Step-by-step explanation:
as the common ratio is multiplying by 3 and the first term is 1 so from the rule (Tn=ar(power n-1 ) )
so the 11th term is 1*3(power 11-1 ) equal 3 power 10 equal 59048
Answer:
3.
Step-by-step explanation:
3(n + 4) = 21
3n + 12 = 21
3n = 21 - 12 = 9
n = 3.
Answer:
0.010
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score = 63 inches
μ is the population mean = 70 inches
σ is the population standard deviation = 3 inches
For x shorter than 63 inches = x < 63
Z score = x - μ/σ
= 63 - 70/3
= -2.33333
Probability value from Z-Table:
P(x<63) = 0.0098153
Approximately to the nearest thousandth = 0.010
Therefore, the probability that a randomly selected student will be shorter than 63 inches tall, to the nearest thousandth is 0.010.
