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4 years ago

9

A bead necklace uses beads whose diameter, d, ranges from 5 millimeters to 8 millimeters (inclusive). The number of beads in a n

ecklace, n, is less than 300.
a. write an inequality describing the diameter of the beads.
b. write an inequality describing the number of beads

1 answer:

wolverine [178]4 years ago

4 0

The Answer is B Cause if u describe the number of beads u will get a correct answer
Hope this Halps :D

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Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 22 h using both

FrozenT [24]

Answer:

correct answer: Bob's hose required alone 33 hours and Jim's hose required alone 66 hours

Step-by-step explanation:

Given:

Bob's hose time = 50% of Jim's hose time ⇒

⇒ Jim's hose time = 2 · Bob's hose time

Let be x Bob's hose time and 2x Jim's hose time

The following equation will solve the problem:

1/x + 1/ 2x = 1/22

The common denominator for both fractions is 2x, so we will multiply the first fraction by the number 2 and get:

2/2x + 1/2x = 1/22 ⇒ 3/2x = 1/22 ⇒ x = 3 · 22 / 2 ⇒ x = 3 · 11 = 33 hours

Bob's hose time x = 33 hours and

Jim's hose time 2x = 66 hours

God is with you!!!

4 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

Clara baked a sheet cake with a length of 0.5 meters. She covered the cake in small 1 frosting polka dots that are the length of

almond37 [142]

Answer:

kkuguftfhbnkmom ugvtvtv uvbuub

4 0

3 years ago

What is the value of the expression (30 - 6b) when b is 3.5

geniusboy [140]

Answer:

9

Step-by-step explanation:

30 - 6(3.5)

30 - 21

9

6 0

3 years ago

CAN SOMEONE HELP PLEASE!!

grandymaker [24]

The predicted time remaining has decreased by 30 years, so the second one would be the answer

3 0

3 years ago