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Savatey [412]
3 years ago
9

What two numbers multiply to get -27 and add to 6

Mathematics
1 answer:
andriy [413]3 years ago
4 0
So in this u will have a negative and a positive so it will be (x-3)(x+9)

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Manny has $650 in his savings
Bumek [7]

Answer:

Interest Manny earns after 2 years is  $52

Step-by-step explanation:

Amount deposited = $650

Simple annual interest rate = 4%

To find: Interest after 2 years

We know that the formula to calculate the interest amount is

Simple interest (S.I.) =  \frac{Prt}{100}

where,

P is the initial amount deposited

r is the rate of simple interest in percentage

t is the time in years for which interest is to be calculated

Substituting the known values in the formula, we get

S.I =  \frac{650 x 4 x 2}{100}

   = 52

Hence the interest Manny earns after 2 years is  $52

8 0
3 years ago
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Jaya has a 10 cm square piece of origami paper. If she folds the square into 4 equal triangles, what will be the area of each tr
Katen [24]
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4 0
3 years ago
Read 2 more answers
4 points
USPshnik [31]

Answer:

C $1.75

Step-by-step explanation:

$469 divided by 268 is $1.75, so it's $1.75 per item

5 0
3 years ago
Write the fact family for 5,8,and 40
Juli2301 [7.4K]
A fact family is basically just different equations with the same numbers getting the same/different numbers as answers you might say... 
this will make more sense: 
5x8=40
8x5=40
40/8=5
40/5=8
4 0
3 years ago
Santos is a lifeguard and spots a drowning child 50 meters along the shore and 60 meters from the shore to the child. Santos run
Amanda [17]

Answer:

Santos should run approximately 36.145 meters along the shore

Step-by-step explanation:

The given parameters are;

The distance along the shore of the child = 50 meters

The distance from the shore of the child = 60 meters

The rate at which Santos can run = 4 m/s

The rate he can swim = 0.9 m/s

Let 'x' represent the distance he runs along the shore

We have;

The time he spends running on the shore, t₁ = x/4

The time he spends swimming, t₂ = (√(60² + (50 - x)²)/0.9

The total time, T = t₁ + t₂ = x/4 + (√(60² + (50 - x)²)/0.9

To find the maximum, we have;

dT/dx = 0 = d(x/4 + (√(60² + (50 - x)²)/0.9)/dx = 1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

Simplifying using a graphing calculator gives;

\dfrac{x - 2000}{9} = \sqrt{x^2-100\cdot x+6,100}

1519·x² - 151900·x + 3505900 = 0

x = (151900 ± √((-151900)² - 4×1519×3505900))/(2 × 1519)

x ≈ 63.86 m or x ≈ 36.145 m

We note that the distance from a point x = 63.83 meters and 36.145 meters from where Santos spots the girl to the location of the girl are the same

Therefore, Santos should run approximately 36.145 meters along the shore before jumping into to the water in order to save the child

7 0
3 years ago
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