Answer:
A
Step-by-step explanation:
if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is
(x-x1)(x-x2)+(y-y1)(y-y2)=0
reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0
center is (2,-4)
r=√(2²+(-4)²-(-14))
=√(4+16+14)
=√(34)
eq. of circle is (x-2)²+(y+4)²=34
or
(x²-4x)+(y²+8y)=14
(x²-4x+4)+(y²+8y+16)=14+4+16
(x-2)²+(y+4)²=34
Answer:
17. 15
18. 8(this one I'm not sure tho what does the right one say)
19. 32
20. 5
The number is 24. If 8 is one third of the number, you multiply 8 by 3 to find the number, which is 24.
Here you have an equation with two unknown constants, a and b, plus 2 sets of points through which the graph goes.
Second point: 96 = a(b)^2
First point: 6 = a(b)^0 Then a = 6.
With a = 6, we can now write: 96 = 6b^2. Then b^2 = 16, and b=4.
Then y =6(4)^x (answer)
