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Nataly_w [17]
3 years ago
5

-4²-5·-4+2 please!!! i really need to know if it is 6

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0

Answer:

9

Step-by-step explanation:

=-4²-5-4+2

=16-5-4+2

=18-9

=9

Hope u like it

<em>PLZ</em><em> </em><em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>BRAINLIEST</em>

tangare [24]3 years ago
4 0

Answer:

The answer is 6!

Step-by-step explanation:

You might be interested in
For } (x) = 4x+1 and g(x) = x2 -5, find (f/g)(x)
matrenka [14]

Answer:

Step-by-step explanation:

                                                           4x + 1

The quotient   (f/g)(x) is    (f/g)(x) = ---------------

                                                          x^2 - 5

Note that x^2 means "square of x," whereas "x2" is ambiguous.

7 0
2 years ago
Subtract: (4n + 7) - (7n - 8)
Furkat [3]
4n+7−(7n−8)

=4n+7+−1(7n−8)

=4n+7+−1(7n)+(−1)(−8)

=4n+7+−7n+8

Combine Like Terms

=4n+7+−7n+8

=(4n+−7n)+(7+8)

=−3n+15

4 0
2 years ago
Pls help which one is it
ValentinkaMS [17]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank
mars1129 [50]

Complete question:

Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.

Answer:

11/288

Step-by-step explanation:

We are given:

Box 1: ( 4White, ORed)

Box 2: (3White, 1Red)

Box 3: (2White, 2 Red)

We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.

Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.

Our Event, E = getting 2 red balls.

Now Box 1 is ruled out, we have:

P[E(B1)]= 0

P[E/B3)] = (2 2) / (4 2)

= 1/6

If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:

P(E/B2) = (1/4) *(1/4)

= 1/16

Therefore probability that 2 balls extracted are red, we have:

P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 0 * \frac{1}{3} + \frac{1}{6}*\frac{1}{3} + \frac{1}{16}*\frac{1}{3}

= 11/288

3 0
3 years ago
10
Sonbull [250]

Answer:

c

Step-by-step explanation:

7 0
2 years ago
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