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3 years ago

What is the equation of the circle if the center is (-4,10) and radius of 7

Mathematics

2 answers:

natulia [17]3 years ago

8 0

The answer will be -2

kvv77 [185]3 years ago

3 0

Answer:

(x+4)^2+(y-10)^2=49

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

where the center is (h,k) and r is the radius

so in this case h=-4, k=10, r=7

then we just plug them in

(x- -4)^2+(y-10)^2=7^2

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ACT help!!

DaniilM [7]

g) c=1.98w is your answer

w = weight = 5.5

c = cost = 10.89

10.89 = 1.98(5.5)

10.89 = 10.89 (true)

hope this helps

8 0

3 years ago

What is the absolute value of a number?

Nadusha1986 [10]

Answer:

All of the whole numbers

Step-by-step explanation:

absolute value" means to remove any negative sign in front of a number, and to think of all numbers as positive

4 0

3 years ago

Read 2 more answers

Help please!! It would be nice if you could add an explanation, but you don't have to. I just need the answer.

Firlakuza [10]

The answer is B I solved this my self

4 0

3 years ago

SUPER URGENT!!!!!!!! I NEED HELP!!!!!1 PLSSSS!!!!!Use the linear combination method to solve the system of equations. Explain ea

Vedmedyk [2.9K]

Answer:

x=-3,y=-2

Step-by-step explanation:

Given 2 expressions

S1: $3x-8y=7$

S2: $x+2y=-7$

Write one equation in terms of any variable (x or y)

Here I am writing S1 in terms of y

$3x-8y=7\\3x-7=8y\\y=\frac{3x-7}{8}$

Substitute this value of y as the value of y in S2

⇒ $x+2y=-7\\x+(\frac{3x-7}{8} )\times2=-7\\8x+6x-14=-56\\14x=-42\\x=-3$

Therefore $x=-3$

Substitute this value of x in any of the expressions S1 or S2

Here i am substituting in S2

⇒ $x+2y=-7\\-3+2y=-7\\2y=(-7+3)\\2y=-4\\y=-2$

Therefore x=-3 and y=-2

6 0

3 years ago

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation of 1.4. The distributio

posledela

Answer:

Approximate probability that $\overline{X}$ is less than 2 = 0.1515

Step-by-step explanation:

Given -

Mean $(\nu )$ = 2.2

Standard deviation $(\sigma )$ = 1.4

Sample size ( n ) = 52

Let $\overline{X}$ be the mean of accidents per week at the intersection during one year (52 weeks) .

probability that $\overline{X}$ is less than 2 =

$P(\overline{X}< 2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}< \frac{2 - 2.2 }{\frac{1.4}{\sqrt{52}}})$ Putting $(Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})$

= $P(Z< - 1.03)$ ( Using Z table )

= 0.1515

7 0

3 years ago