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AveGali [126]
3 years ago
13

A set of data already has the values 11, 14, 23, and 16. What value would have to be added to the set for the mean of the

Mathematics
1 answer:
ad-work [718]3 years ago
6 0
Your answer is 26.

We have to go at this kind of backward.

We find the average by adding up the numbers, then dividing by how many numbers we have.

In this example, we will have 5 numbers...so
x divided by 5 = 18

x/5 = 18
x = 90

The sum of all 5 numbers is 90, so then subtract the 4 numbers you already know to find the one you’re missing. (We’ll call it n)

90 - 8 - 12 - 18 - 26 = n

90 - 64 = n
n = 26

Please let me know if you have any questions.

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Dana randomly selected ten different brands of soda and recorded the number of calories in a 12 ounce serving size. They were as
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Answer:

65 i believe

Step-by-step explanation:

first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

7 0
3 years ago
The 24 students in ms. lees class each collected an average of 18 cans for recycling. then 21 students in mr. galvez's class eac
belka [17]

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3 years ago
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umka2103 [35]
2b + 34greater then or equal to 54

5 0
3 years ago
How to do this problem??
lorasvet [3.4K]
We know that the sum of the inner angles of any triangle is 180º

72º + (7x + 3)º + (3x + 5)º = 180º
72º + 7xº + 3º + 3xº + 5º = 180
7xº + 3xº = 180º - 72º - 3º - 5º
10xº = 100º
x^0 =  \frac{100^0}{10^0}
x^0 = 10\to\:\boxed{\boxed{x = 10^0}}\end{array}}\qquad\quad\checkmark

The sum of the external angle (9y + 1)º with inner angle (3x + 5) = 180 °, <span>Replace the measure of "x" found:
</span>
(9y + 1)º + (3x + 5)º = 180º
9yº + 1º + 3xº + 5º = 180º
9yº + 1º + 3.(10)º + 5º = 180º
9yº + 1º + 30º + 5º = 180º
9yº = 180º - 1º - 30º - 5º
9yº = 144º
y^0 =  \frac{144^0}{9^0}
y^0 = 16\to\:\boxed{\boxed{y = 16^0}}\end{array}}\qquad\quad\checkmark

Answer:
<span>The measures ​​of "x" and "y" are respectively: 10º and 16º</span>
6 0
3 years ago
Name the types of angles shown.
PIT_PIT [208]
< ABC is a straight angle
no right angles
no complimentary angles
< ABD and < DBC are supplementary angles


7 0
3 years ago
Read 2 more answers
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