All categories

3 years ago

The ratio of 600m to 3km in simplest form

Mathematics

1 answer:

never [62]3 years ago

6 0

3 km = 3000m
600m:3000m divide by 10
60:300 divide by 10
6:30 divide by 3
2:10 divide 2
*1:5* (simplest form)

You might be interested in

PLS HELP ME ITS DUE IN 4 MINS!<br><br> Subtract 2y²+7y+2 from 6y²+9y−8.

Dmitry_Shevchenko [17]

Answer:

-4y^2 - 2y + 10

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

I need help with know number 5 and 6 can anyone help me

LenaWriter [7]

Give me a min i need to think but ill get back to you as soon as possible

3 0

3 years ago

Rationalise the denominator of:<br>1/(√3 + √5 - √2)

Paul [167]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} }$

can be re-arranged as

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} - \sqrt{2} + \sqrt{5} }$

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} }$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} } \times \dfrac{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }$

We know,

$\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}$

So, using this, we get

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ {( \sqrt{3} - \sqrt{2} )}^{2} - {( \sqrt{5}) }^{2} }$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{3 + 2 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{5 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{ - ( - \sqrt{3} + \sqrt{2} + \sqrt{5}) }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}}$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}} \times \dfrac{ \sqrt{6} }{ \sqrt{6} }$

$\rm \: = \: \dfrac{- \sqrt{18} + \sqrt{12} + \sqrt{30}}{2 \times 6}$

$\rm \: = \: \dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}$

$\rm \: = \: \dfrac{- 3\sqrt{2} + 2 \sqrt{3} + \sqrt{30}}{12}$

Hence,

$\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} } =\dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}}}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h3><u>More Identities to </u><u>know:</u></h3>

$\purple{\boxed{\tt{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{3} = {x}^{3} + 3xy(x + y) + {y}^{3}}}}$

$\purple{\boxed{\tt{ {(x - y)}^{3} = {x}^{3} - 3xy(x - y) - {y}^{3}}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}}}$

6 0

3 years ago

Use the graphs to estimate both solutions to x^2+x-4=0

Bogdan [553]

Answer:

No graph so we'll use the quadratic formula

x^2+x-4=0

a = 1

b = 1

c = -4

x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2

x = (-1 +- sqr root (1 +16) ) / 2

x1 = (-1 + sqr root (17)) / 2

x2 = (-1 - sqr root (17)) / 2

Step-by-step explanation:

4 0

3 years ago

Brainliest ! 40 points , pls answer all or don't answer

MAVERICK [17]

Answer:

The answer to your question is below

Step-by-step explanation:

1.- Find the volume of the cylinder

Data

diameter = 9 cm

radius = 4.5 cm

height = 15 cm

Formula

V = πr²h

V = π(4.5)²(15)

V = 303.75π This is te answer for the volume in terms of π

= 952.78 cm³

2.- Find the volume of the cylinder

height = 40 yd

radius = 12 yd

Formula

V = πr²h

V = π(12)²(40)

V = 5760π This is te answer for the volume in terms of π

= 18086.4 cm³

3.- What is the height .......

height = q

side length = r

4.- Volume of a pyramid

Volume = Area of the base x height

Area of the base = 11 x 11 = 121 cm²

Volume = 121 x 18

Volume = 2178 cm³

6 0

3 years ago

Read 2 more answers