Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.
H²+10h+21 = 0
h²+3h+7h+21 = 0
h(h+3)+7(h+3) = 0
(h+3)(h+7) = 0
h+3=0
h = -3
h+7=0
h=-7
Answer:
See image.
Step-by-step explanation:
Remember if you have a right angle inside of a circle, the hypotenuse is going to land exactly on the diameter. Also, Area of a circle = (pi)r^2 Lastly, remember pythagorean triples such as 3,4,5 or at least, the Pythagorean theorem a^2 + b^2 = c^2
Answer:
1,924,972.486 ks
Step-by-step explanation:
I think this is right... sry if its wrong though