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GenaCL600 [577]
3 years ago
11

HELP PLEASE BEST ANSWER WILL BE MARK AS BRAINLIEST!

Mathematics
1 answer:
Gwar [14]3 years ago
8 0
First of all,
The total weight of the six dogs are:
71+34+15+23+18+56=217 pounds
Then, we know that the average weight of the seven dogs are 40 pounds, so the total weights of the seven dogs are:
40×7=280 pounds.
Lastly, we know that the six dogs weights are 217 pounds and the total weight of the seven dogs are 280 dogs, so the seventh weight of the dog is:
280-217=63 pounds. As a result, the seventh weight of the dogs at the vet is 63 pounds. Hope it help!
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ludmilkaskok [199]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
AC = 2x+24<br>DB = 5x-3 solve for x​
snow_lady [41]
  1. 2x+24
  2. 2÷2 25÷2
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1. 5x-3

2. 5÷5 -3÷5

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4 years ago
Squeezy fruit drink is 36% pure orange juice and 64% water, if 1 L of Squeezyfruit drink is mixed with 600 mL of water what is t
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3 0
3 years ago
The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h
BabaBlast [244]

Answer:

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Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

K

in this case is 90 and thus, that is the maximum height of the projectile

8 0
3 years ago
Please help me on this question
Mice21 [21]
8+2m^3 is the answer. Hope it help!
6 0
4 years ago
Read 2 more answers
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