What is 1-2*30 answer pls

A company rents water tanks shaped like cylinders. Each tank has a radius of 3 feet and a height of 2 feet. The cost is $4 per c

vivado [14]

Answer:

Cost to rent one tank=226.08 Dollars

Step-by-step explanation:

Radius of the cylindrical tank=3 feet

Height of the tank= 2 feet

Cost to rent one tank= Volume of one tank * cost to rent one cubic feet of volume

Volume of the cylindrical tank:

= $\pi r^2$

As, $\pi =\frac{22}{7}=3.14$

Putting the values in the formula:

Volume of the tank:

$=3.14*(3*3)*2\\\\=3.14*9*2\\\\=3.14*18\\\\=56.52feet^3$

Cost to rent one cubic feet= 4 Dollars

Cost to rent 56.52 Cubic feet of one tank;

= 4*56.52

=226.08 Dollars

5 0

3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

3 years ago

Shirley has a collection of 50 stamps and adds 4 stamps daily to her collection. model this situation as a function of number of

kompoz [17]

Stamps - S

S= 50+ 4d

Sorry if I’m wrong

4 0

2 years ago

Determine the quadratic inequality that produces the graph below. HELP ASAP!

svetlana [45]

Answer:

believe it's option C but not 100 percent sure.

Step-by-step explanation:

I'm not good at explaining.

4 0

3 years ago

Shreya and beth each improved their yards by planting rose bushes and ornamental grass. They brought their supplies from the sam

frutty [35]

Answer:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

Explanation:

Name the variables and build a system of two equations with two unknowns.

1. Variable r: cost of one rose bush

2. Variable g: cost of one bunch of ornamental grass.

3. First equation:

Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

4r + 4g = 68

4. Second equation:

Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

11r + 2g = 115

5. System of equations:

4r + 4 g = 68 equation 1

11r + 2g = 115 equation 2

6. Solve the system

a) Divide the equation 1 by 2:

2r + 2g = 34 equation 1a

11r + 2g = 115 equation 2

b) Subtract equation 1a from equation 2:

11r - 2r = 115 - 34

9r = 81

r = 81 / 9

r = 9

c) Substitute the value of r into the equation 1a:

2(9) + 2g = 34

9 + g = 17

g = 17 - 9

g = 8

7. Conclusion:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

7 0

3 years ago