Question

EC = 10cm, AE = 4cm, and m∠EAB = 45°. Find the area of the kite. 56cm2 80cm2 112cm2 160cm2

Answer 1

Answer:

Option A is correct i.e Area is 56 square centimeter.

Step-by-step explanation:

Given EC = 10cm, AE = 4cm, and m∠EAB = 45°. we have to find the area of kite.

In ΔABE,  ∠EAB = 45°

$tan\angle EAB=\frac{BE}{AE}$

⇒ $tan 45^{\circ}=\frac{BE}{4}$

⇒ BE=4 cm

BE=ED=4 cm (one diagonal of kite bisect other)

BD=BE+ED=4+4=8 cm

AC=AE+EC=4+10=14 cm

$\text{Area of kite=}\frac{pq}{2}$, where p and q are the diagonals

⇒ $\text{Area of kite ABCD=}\frac{8\times 14}{2}=56cm^2$

Option A is correct.

Answer 2

Did the math the comment bro is right it’s 56