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Virty [35]
3 years ago
14

At a bake sale there were 90 items sold total. If 42 of the items sold were cookies and the rest were brownies what is the ratio

of brownies sold to cookies sold?
Mathematics
1 answer:
kari74 [83]3 years ago
5 0
Firstly, you do 90 - 42 to get the amount of brownies sold, which is 48. Then, you put 42 and 48 into a ratio like 42:48. After that, all you need to do is simplify to get 7:8.
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Each egg carton holds one dozen eggs. Michael's chicken farm fills 121 egg cartons. He thinks that there were over 1500 eggs. Is
Kobotan [32]
121 x 12 = 1452 so over 1500 is not a correct estimate. Less than 1500 is the right estimate
3 0
3 years ago
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
How do you solve 3/5 times 2/3
UkoKoshka [18]
Hello! And thank you for your question!

First use the rule: A/b x c/d = ac/bd

3 x 2 over 5 x 3

Simplify 3 x 2:

6 over 5 x 3

Simplify 5 x 3:

6/15

Simplify further:

2/5

Final Answer:

2/5
3 0
3 years ago
If f(x) = 3x^2 - 4 and g(x) = x+2, find (f - g)(x).
galina1969 [7]

Answer:

3x^2-x-6

Step-by-step explanation:

f(x) = 3x^2 - 4

g(x) = x+2

(f - g)(x)= 3x^2 - 4-( x+2)

Distribute the minus sign

(f - g)(x)= 3x^2 - 4- x-2

Combine like terms

            = 3x^2-x-6

8 0
3 years ago
Read 2 more answers
Rewrite using factors and exponents, then simplify<br> 1. 1000/100 2. 9/81 3. 4/64
marta [7]
1) 1000 / 100 ⇒ 10 / 1 = 10
1000 ÷ 100 = 10
  100 ÷ 100 =   1

2) 9/81 ⇒ 1/9
  9 ÷ 9 = 1
81 ÷ 9 = 9 

3) 4/64 ⇒ 1/16
  4 ÷ 4 =   1
64 ÷ 4 = 16
4 0
3 years ago
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