0.36363636363 is the answer
Answer:
The probability of the bus getting there BEFORE 8:20 isn't likely
I took an average of all of the numbers and its shows that he bus will be there about 8:20.25
Answer:
<em>The dimensions of the tabletop: Length= 67.976... inches and Width= 33.988... inches and the perimeter will be 203.929... inches.</em>
Step-by-step explanation:
Suppose, the width of the rectangular tabletop is 
inch.
As the tabletop has a length that is twice it’s width, so the length will be: 
inch.
The tabletop measures 76 inches on its diagonal.
<u>Formula for length of diagonal of rectangle</u>: 
So, the equation will be..........
Thus, the width of the tabletop is 33.988... inches and the length will be: (2×33.988...) = 67.976... inches.
The perimeter will be: 2(33.988...+ 67.976...) inches = 203.929... inches.
First you need to divide 64 by 75 and then multiply by 100 which is 85.3% which then you need to find the average of the 2 which will be (85.3+x)/2=88 where x= the value of the second test.
Then you will need to isolate the x with the following steps:
- multiply each side by 2 making it 85.3+x=176
- Subtract 85.3 from each side
- this results in 90.7
NOT MY WORDS TAKEN FROM A SOURCE!
(x^2) <64 => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2 so (x^2) - (8^2) < 0 To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y) You can work backwards and verify this is true. so let's set (x^2) - (8^2) equal to zero to find the roots: (x^2) - (8^2) = 0 => (x-8)*(x+8) = 0 if x-8 = 0 => x=8 and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0 so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.
Hope this helped!
:)
