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creativ13 [48]
3 years ago
6

Must do this to get the other question answer

Mathematics
2 answers:
Arlecino [84]3 years ago
4 0
To solve this:
a + 9 = 36
a = 36 - 9
a = 27
Hope This Helps!!!

weeeeeb [17]3 years ago
3 0
So what exactly is the question

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A locus of points equidistant from a fixed point is a
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Answer:

B. bisector of an angle.

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3 years ago
A juice company produces 8,064 cartons of juice in 21 days. Each day, they produced the same number of cartons and delivered tho
KatRina [158]
8064 cartons in 21 days......8064/21 = 384 cartons per day

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64/16 = 4.....so each coffee shop received 4 cases per day <==
7 0
3 years ago
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The five-number summary of the ages of passengers on a cruise ship is listed below. Min 1 Q1 20Median 29 Q3 38Max 80 Consider th
Eddi Din [679]

Answer: b. Only statement (ii) is correct.

Step-by-step explanation:

The given five-number summary of the ages of passengers on a cruise ship is listed below.

Min 1    Q_1 20     Median 29     Q_3 38         Max 80

Inter-quartile range = IQR=Q_3-Q_1=38-20=18

  • According to the 1.5(IQR) criterion for outliers : An data value is an outlier if it lies below Q_1 - 1.5(IQR) or  above Q_3 + 1.5(IQR).

Here , Q_1 - 1.5(IQR) =20-1.5(18)=-7

Q_3 + 1.5(IQR)=38+1.5(18)=65

Since the minimum value> Q_1 - 1.5(IQR) ( ∵ 1 > -7)

It means there is no value below Q_1 - 1.5(IQR)  , so there is no low -outlier.

⇒ Statement (i) "here is at least one passenger whose age is a low outlier. " is false.

But the maximum value > Q_3 + 1.5(IQR) (∵  85 > 65)

It means there are values above Q_3 + 1.5(IQR).

⇒Statement (ii) "There is at least one passenger whose age is a high outlier" is true.

Hence, the correct answer is b. Only statement (ii) is correct.

8 0
3 years ago
A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card
Reil [10]
Number of red cards including 2 red queens = 26
Number of black queens = 2
Therefore, number of red cards including 2 red queens and 2 black queens = 26 + 2 = 28
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P  =  \frac{ Number \: of \: favourable \: outcomes}{ Total \: numer \: of \: possible \: outcomes}

P (neither \: a \: red \: nor \: a \: queen \: card \: ) =  \frac{24}{52}  =  \frac{6}{13}
8 0
4 years ago
HELP ME, HELP ME, HELP ME, HELP ME!!!!!!!!!!!!!!
lord [1]
The answer is all nonzero real numbers. I've had this problem before
8 0
3 years ago
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