20. Please help I really need it

How do you factor (y^4-x^9) ? <br><br> Thank you

polet [3.4K]

So since you know that x^2-1 is equal to (x-1)(x+1),
you can figure that this factors to
(y^2-x^3)(y^2+x^3)
because you know how the difference of two squares formula, stated on the top line of this answer.

5 0

2 years ago

I need the answer quick

Vanyuwa [196]

Answer:

the order pairs show us how many feet the hot air balloon rises in a certain amount of seconds

Step-by-step explanation:

6 0

2 years ago

Two boys searching for buried treasure are standing underneath the same tree. one boy walks 12 m east and then 12 m north. the o

mylen [45]

Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2

5 0

3 years ago

What is the solution to the equation below? 4(3x + 5) = 5(x + 4) + 7x A infinite solutions OB no solution 0 со D 3

Alex787 [66]

Answer: All Numbers Are Real Solutions (Note - Have An Amazing Day! :)

Comment If I'm Wrong!

Step-by-step explanation:

4(3x+5)=5(x+4)+7x

(4)(3x)+(4)(5)=(5)(x)+(5)(4)+7x

12x+20=5x+20+7x

12x+20=(5x+7x)+(20)

12x+20=12x+20

12x+20−12x=12x+20−12x

20=20

20−20=20−20

0=0

Answer: All real numbers are solutions

4 0

3 years ago

Read 2 more answers

Which are the solutions of x2 = –13x – 4? 0, 13 0, –13 StartFraction 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma Sta

klasskru [66]

Solution of the given expression $x^2 = -13x-4$ is $x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Step-by-step explanation:

We need to find solutions of $x^2 = -13x-4$

We need to solve the quadratic equation and find values of x.

Solving:

$x^2 = -13x-4$

Rearranging the terms:

$x^2+13x+4=0$

Solving the quadratic equation using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a = 1, b= 13 and c=4

putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(13)\pm\sqrt{(13)^2-4(1)(4)}}{2(1)}\\x=\frac{-13\pm\sqrt{169-16}}{2}\\x=\frac{-13\pm\sqrt{153}}{2}\\x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

So, Solution of the given expression $x^2 = -13x-4$ is $x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

#learnwithBrainly

5 0

2 years ago

Read 2 more answers

20. Please help I really need it​

20. Please help I really need it