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3 years ago

5miles = 8km. How many km in 250 miles?

2 answers:

7 0

You can make a proportion
5 250
--- = ------
8 x

then cross multiply and divide. 8 times 250 =2000/5=400

250 miles are 400 km

Kay [80]3 years ago

4 0

5 miles ... 8 km
250 miles ... x km = ?

If you would like to know how many km equals to 250 miles, you can calculate this using the following steps:

5 * x = 8 * 250 /5
x = 8 * 250 / 5
x = 400 km

The correct result would be 400 km.

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A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w

sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

7 0

3 years ago

Fine the slope of the line through each pair of points . (-8,-20),(5,2)

kozerog [31]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-8, -20) and (5, 2). Substitute:

$m=\dfrac{2-(-20)}{5-(-8)}=\dfrac{22}{13}$

Answer: The slope is $\dfrac{22}{13}$

7 0

4 years ago

Read 2 more answers

-8x+2y=-2 4x+4y=-4 What is the solution to the system

pickupchik [31]

The solution to system is x = 0 and y = -1

Solution:

Given system of equations are:

-8x + 2y = -2 ----------- eqn 1

4x + 4y = -4 ---------- eqn 2

We have to solve the system of equations

We can solve the equations by elimination method

Multiply eqn 2 by 2

8x + 8y = -8 ------ eqn 3

Add eqn 1 and eqn 3

-8x + 2y = -2

8x + 8y = -8

( + ) ---------------

0x + 2y + 8y = -2 - 8

10y = -10

Divide both sides by 10

y = -1

Substitute y = -1 in eqn 1

-8x + 2(-1) = -2

-8x - 2 = -2

-8x = -2 + 2

x = 0

Thus the solution to system is x = 0 and y = -1

3 0

3 years ago

Question 2 Solve by substitution. 2x – 10y = 14 2x + 6y = -2

Fed [463]

Answer:

x= 2 and y= -1

Step-by-step explanation:

x=7 +5y

14+16y=−2

y=−1

Substitute y=-1y=−1 into x=7+5yx=7+5y.

x=2

8 0

3 years ago

Please answer both thank you

jeyben [28]

Answer:

Solution given;

male=15

female=27

1st term=5*3

2nd term=3*3*3

now

Highest common factor=3

The maximum number of groups that the teacher can make is 3.

and each team contains 5 male and 9 female.

7 0

3 years ago