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wariber [46]
2 years ago
15

HELP ASAP PLEASE!!!

Mathematics
1 answer:
grigory [225]2 years ago
7 0

The quadratic fomula:

ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\If\ \Delta0,\ then\ \boxed{TWO\ SOLUTIONS:\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}}-----------------------------------------------

We have the equation:

2x^2-7x-21=0\\\\a=2,\ b=-7,\ c=-21\\\\\Delta=(-7)^2-4(2)(-21)=49+168=217 > 0\\\\x_1=\dfrac{-(-7)-\sqrt{217}}{2(2)}=\dfrac{7-\sqrt{217}}{4}\approx-1.93\\\\x_2=\dfrac{-(-7)+\sqrt{217}}{(2)(2)}=\dfrac{7+\sqrt{217}}{4}\approx5.43\\\\Answer:\ \boxed{\boxed{2.\ -1.93\ and\ 5.43}}

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The difference between two positive integers is 7 and the sum of their squares is 949. What are the numbers?
Darina [25.2K]

Answer:

25 and 18

Step-by-step explanation:

Let's say that the first number is x and the second one is y.

First, the difference between them is 7, so x-y=7

Next, the sum of their squares is 949, so x²+y² = 949

We have

x-y=7

x²+y²=949

One thing we can do to solve this problem is to solve for x in the first equation, plug that into the second equation, and go from there

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expand

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49 + y² + 7y + 7y + y² = 949

combine like terms

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subtract 949 from both sides to put this in the form of a quadratic equation

2y² + 14y - 900 = 0

divide both sides by 2

y² + 7y - 450 = 0

To factor this, we want to find 2 numbers that add up to 7 and multiply to -450.

The factors of 450 are as follows:

1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, and 450.

Note that we want to find two numbers with a difference of 7, as one will have to be negative for the multiplication to end up at -450. Two numbers that stand out are 18 and 25. To make them add up to 7, 18 can be negative. We therefore have

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As the question states "two positive integers", this means that y must be positive, so y = 18. We know x-y=7, so

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add 18 to both sides to isolate x

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The answer to this question is:
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