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kirill115 [55]
3 years ago
7

The question is 7a +10 = 2a

Mathematics
2 answers:
Amanda [17]3 years ago
8 0
 7a + 10 = 2a  subtract 2a from both sides
-2a          -2a
 5a + 10 = 0    subtract 10 from both sides
       -10    -10
5a = -10          then divide both sides by 5
/5      /5
a = - 2
Sergeeva-Olga [200]3 years ago
4 0
7a+10=2a
Subtract 7a from both sides.
10=-5a
Divide 10 by -5.
-2=a or a=-2
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What is the best first step for solving the equation 5 = 3x - 4? a. Add 4 to both sides of the equation. b. Subtract 4 from both
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Read 2 more answers
What is the product of (2x-7) and (3x + 3)?
eduard
<h3>✒️EVALUATION </h3>

==================================

\large\sf\underline{Problem:}

What is the product of (2x-7) and (3x + 3)?

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

==================================

\large\sf\underline{Answer:}

\qquad \qquad \huge \rm Letter\:B.

*Please read and understand my solution. Don't just rely on my direct answer*

==================================

\large\sf\underline{Solution:}

Here we have the given choices:

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

Solve this equation using the distributive property,where you multiply each term to get the number.

\begin{gathered} \rm2x - 7 = \boxed{ 6} \: \bigg| \small\boxed{\: 6 {x}^{2} } \\ \rm (7)(3) = \boxed{21} \bigg | \boxed{\: 21 x} \\ \\ \qquad \rm6x^{2}+(6x- 21x)-21 \\ \qquad \boxed{ \rm6 {x}^{2} + 15x - 21}\end{gathered}

Therefore, the correct option is letter B.

==================================

ヾ(^-^)ノ

3 0
2 years ago
Change one digit from the number 238882 so that it is divisible by 3 not not divisible by 2
Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

To make it not divisable by 2, you have to change the rightmost digit.

Simply divide the number by 3, round it, then multiply it by 3 again.

6 0
2 years ago
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