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Aleks [24]
3 years ago
10

Mario travels 180 miles in 2.5 hours if Mario travels at the same re how for can Mario travel in 10 hours

Mathematics
1 answer:
Bad White [126]3 years ago
4 0

Answer:

720 miles

Step-by-step explanation:

180mi/2.5hr=72 mph

72mph (10hr)=720 miles

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Lawrence wants to drive from Durban to Johannesburg 550km. If he travels at an average speed of 100km/hr, how long does he tale
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5.5hr

Step-by-step explanation:

Distance=550Km

Speed=100Km/hr

Speed=(Distance/Time)

Time=(Distance/Speed)

Time=550/100=5.5hr

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3 years ago
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What is the common ratio for 128, 96, 72, 54,....
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Step-by-step explanation:

r=96/128=3/4

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How many millimeters are in 1 meter? Use the metric table to help answer the question.
AlekseyPX

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2 years ago
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In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

4 0
2 years ago
TWO QUESTIONS PLS HELP ASAP
ASHA 777 [7]
Answer: 4. (-1,-1) 3. (3,-2)

4)

Set the equations equal to each other.

4x+3=-x-2

Subtract 3 from both sides

4x=-x-5

Add x to both sides

5x=-5

Divide both sides by 5

x=-1

Next, replace x with -1 in either equation to find y.

-(-1)-2=y

-1=y


3)

Do the same thing for this one and set them equal to each other

-2x+4=-1/3x-1

Add 1 to both sides

-2x+5=-1/3x

Add 2x to both sides

5=5/3x

Divide both sides by 5/3

x=3

Next, replace x with 3 in either equation

-2(3)+4=y

-2=y




4 0
3 years ago
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