Answer:
A=L*W
Let w be width
L=(w+6)
40=(w+6)*w
40= w^{2} +6w
w^{2} +6w-40=0
w^{2}+10w-4w-40=0
w(w+10)-4(w+10)=0
(w-4)(w+10)=0
w=4
Length= 10 units
Width=4 units
Step-by-step explanation:
You add 8 and 5 so the equation would be 8+5=13
Answer:
Step-by-step explanation:
I wish I knew :(
Simplified: x^3+5x^2-2x+1
in standard form: x^3+5x^2-2x+1
There isn't enough info to prove the triangles to be congruent or not. So we can't say for sure either way.
We have angle CAD = angle ACB given by the arc markings, and we know that AC = AC due to the reflexive theorem. However we are missing one third piece of information.
That third piece of info could be....
- AD = BC which allows us to use SAS
- angle ACD = angle CAB which allows us to use ASA
- angle ABC = angle CDA which allows us to use AAS (slight variation of ASA)
Since we don't know any of those three facts, we simply don't have enough information.
side note: If AB = CD, then this leads to SSA which is not a valid congruence theorem. If we had two congruent sides, the angle must be between the two sides, which is what AD = BC allows.
