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Sedbober [7]
2 years ago
8

Helen had $330 in her savings account when Vince opened a savings account with zero dollars.

Mathematics
2 answers:
aleksley [76]2 years ago
8 0

Answer:

a

Step-by-step explanation:

natka813 [3]2 years ago
3 0

Answer:

B

Step-by-step explanation:

You might be interested in
A line has this equation: y= -9x-2
tia_tia [17]

Answer:

y = - 9x + 15

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 9x - 2 ← is in slope- intercept form

with slope m = - 9

Parallel lines have equal slopes, thus

y = - 9x + c ← is the partial equation

To find c substitute (2, - 3) into the partial equation

- 3 = - 18 + c ⇒ c = - 3 + 18 = 15

y = - 9x + 15 ← equation of parallel line

8 0
3 years ago
After plotting the data where x represents the length of the side of a polygon, and f(x) represents the area of the polygon, Jac
Zigmanuir [339]

Answer:

See the attachment

Step-by-step explanation:

It is convenient to use a spreadsheet or graphing calculator for this.

3 0
3 years ago
Read 2 more answers
Help me with this lol value of( 2^3)^2
ss7ja [257]

Answer:

64

Step-by-step explanation:

first, we'll start with the value inside the parenthesis, which is 2³

2³ means to multiply 2 by itself 3 times

so it would be

2×2×2=8

which then means that the expression is now (8)²

now we need to do (8)², which is to multiply 8 by itself twice

8*8=64

hope this helps!

6 0
2 years ago
Which two tables represent the same function?
topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

  (x2 , y2) is \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ \frac{y-8}{x-4}=\frac{7-8}{6-4}

∴ \frac{y-8}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ \frac{y-5}{x-4}=\frac{4-5}{6-4}

∴ \frac{y-5}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ \frac{y-8}{x-2}=\frac{5-8}{8-2}

∴ \frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ \frac{y-10}{x-2}=\frac{14-10}{6-2}

∴ \frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ \frac{y-9}{x-2}=\frac{6-9}{8-2}

∴ \frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0
3 years ago
If the two lines 2x+y=0 and y=3 are plotted on a typical xy coordinate grid, at which point will they intersect?
erastovalidia [21]
(-1.5,3) Y=3 which is up 3 and a horizontal line and 2x+y=0 can be written as y=-2x so in order to get -1.5 you have to make y=3 cause y=3 and when you do that it should look like 3/-2=-2/-2x so x=-1.5
5 0
3 years ago
Read 2 more answers
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