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nikklg [1K]
3 years ago
10

David and muriel listed these items. what is their net worth?

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Your answer will be 13,331 because you add up all the asset and subtract all the liabilities

Sergeu [11.5K]3 years ago
5 0

Answer:

Option D.

Step-by-step explanation:

To calculate the net worth we subtract the liabilities from the assets.

Total assets

Checking and savings   $6432

Automobile                     $8345

Apartment contents       $5242

Valuables                        $867

                               -------------------------

                Total               $20886

Total Liabilities

Auto loan                       $2820

Credit card                     $1181

Other loans                    $3554

                              ---------------------------

                 Total              $7555

Net worth = Assets - liabilities

                = $20886 - $7556

                = $13331

Option D is the answer.  

                             

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A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

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Step-by-step explanation:

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