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4 years ago

A small smooth ring R of weight 8.5N is threaded on a light inextensible string. The ends of the

Mathematics

1 answer:

Crazy boy [7]4 years ago

3 0

You did the one last to it on the bored.

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X = y = m ∠ H = m ∠ G =

Lorico [155]

Answer:

x=53

y=26

H=106

G=93

Step-by-step explanation:

By the inscribed quadrilateral conjecture:

$2x+(x+21)=180\\(3y+9)+(4y-11)=180\\3x+21=180\\3x=159\\x=53\\7y-2=180\\7y=182\\y=26\\H=2(53)=106\\G=(4(26)-11)=104-11=93$

Hope this helps!

4 0

4 years ago

Help me find the slope

Alex Ar [27]

M= -6/5
hope this helped!!

4 0

3 years ago

Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)

AlekseyPX

Answer:

The approximate solution to the system is $(-2.7, 2.1)$ .

Step-by-step explanation:

To solve the system of equations $\begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$ you must:

$\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$

$\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7$

$\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1$

The approximate solutions to the system of equations are:

$x=-2.7 ,\:y=2.1$

5 0

4 years ago

Read 2 more answers

ms. Cho bought 1/3 yard of wool and 5/8 of oil. the wool cost $9 per yard and the silk $12 per yard. how much did Ms. Cho spend

iren [92.7K]

Wool = $3
Silk = $7.5
So $10.50 in total.
Hope it helps!

3 0

3 years ago

Read 2 more answers

Please answer this question! 20 points and brainliest!

azamat

Step-by-step explanation:

You have to substitute... 0, 5, & 10, & 3

y = 2x + 3

y = 2(0) + 3

y = 0 + 3

y = 3

(0,3)

y = 2x + 3

y = 2(5) + 3

y = 10 + 3

y = 13

(5,13)

y = 2x + 3

y = 2(10) + 3

y = 20 + 3

y = 23

(10,23)

y = 2x + 3

y = 2(3) + 3

y = 6 + 3

y = 9

(3,9)

5 0

3 years ago