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Andrei [34K]
3 years ago
7

Please help me answer part (iii) in the photo.

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0
A.) v = πr​^2​​h
v = π (20^2) * 50
v = π (400*50)
v = 20,000π

B.) v = πr​^2​​h
v = π (4^2) * 10
v = π (16*10)
v = 160π

C.) 20,000π ÷ 160π = 125π
So, it can fill 125 mugs.
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Determined if the graph represents a polynomial function if it does determine the number of turning points and the least degree
skelet666 [1.2K]
  • <em>The graph of f is a polynomial function</em>
  • <em>There are two turning points, namely, x = 0  and x = -2</em>

<h2>Explanation:</h2>

A polynomial function in one variable is given by the form:

f(x)=a_{n}x^n+a_{n-1}x^{n-1}+\cdots +a_{2}x^2+a_{1}x+a_{0}

Since you haven't provided any expression, I'll choose the following function:

f(x)=x^{3}+3x^{2}+3

So this is indeed a polynomial function. A turning point is an x-value where we have either a local maximum or local minimum. So we need to take the derivative of this functions:

f'(x)=3x^2+6x \\ \\ Finding \ turning \ points: \\ \\ 3x^2+6x=0 \\ \\ x(3x+6)=0 \\ \\ \\ So: \\ \\ x=0 \\ \\  and \\ \\ \ 3x+6=0 \therefore \ \boxed{x=-2}

Conclusion:

  • <em>The graph of f is a polynomial function</em>
  • <em>There are two turning points, namely, x = 0  and x = -2</em>

<em />

<h2>Learn more:</h2>

Polynomial function: brainly.com/question/13729121

#LearnWithBrainly

7 0
3 years ago
If a1 = 3 and an = (an-1)^2+4 then find the value of a4
NeX [460]

Answer:

Here is the ans hope it helps:)

8 0
2 years ago
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
3 years ago
Dose anyone know the answer to this question
marishachu [46]

Answer:

Option D!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A 6 pound bag of oranges cost 6.78 What is the unit price?
oksano4ka [1.4K]

Answer:

$1.13

Step-by-step explanation:

Since 6 pound bag of oranges costs $6.78...

\frac{6.78}{6}

Now, let's divide 6.78 in to 6 to find our unit price.

\frac{1.13}{1}

Now we know 1 pound, (our unit price), costs...

$1.13

5 0
4 years ago
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