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3 years ago

aA shopkeeper Sold His goods for rupees 16950 25 discount and then 13 % sales tax. find the amount of discount ?

Mathematics

2 answers:

adoni [48]3 years ago

5 0

RIGHT JUST DO IT PLEASE

goblinko [34]3 years ago

4 0

Answer:

IDK TBH

Step-by-step explanation:

JUST DO IT

-NIKE

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Which lines have slope -4/5 and contain point (0,1)?

Oksanka [162]

I believe it was BC, to find that answer, you simply find the point (0,1) where 0 is x and y is 1. There were two lines which made me not think twice but since it is negative, the lines should be going to the left side rather than the right. So the slope which is y over x of -4/5, to find that, you count up 4 and over 5

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3 years ago

Which ones are the distance formula and midpoint formula?

lutik1710 [3]

Answer:

The distance formula is $d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)2}$

The midpoint formula is $\left(\frac{x_1\:+x_2}{2}\right),\left(\frac{y_1-y_2}{2}\right)$

Step-by-step explanation:

apply the pythagorean theorem on a coordinate grid

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3 years ago

Which value is the furthest from 0 on the number line?

evablogger [386]

Answer:-21.5

Step-by-step explanation:

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4 years ago

Read 2 more answers

lara31 [8.8K]

Answer:

Step-by-step explanation:

Given the points J (1,-10) and K (7, 2)

From the section formula

$(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)$

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is obtained using the formula:

$y=\dfrac{my_2+ny_1}{m+n}\\m=5, n=1, y_1=-10, y_2=2\\Therefore:\\y=\dfrac{5*2+1*-10}{5+1}\\=\dfrac{10-10}{6}\\=0$

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is 0.

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3 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

8 0

3 years ago

aA shopkeeper Sold His goods for rupees 16950 25 discount and then 13 % sales tax. find the amount of discount ?​

aA shopkeeper Sold His goods for rupees 16950 25 discount and then 13 % sales tax. find the amount of discount ?