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andre [41]
3 years ago
15

a residential complex has a square flower bed. the groundskeeper has decided to increase the area of the flower bed by 7 square

feet
Mathematics
2 answers:
AfilCa [17]3 years ago
8 0

Answer:l

Step-by-step explanation:

l

Vlad1618 [11]3 years ago
3 0

Answer:

5=√ x+7

Step-by-step explanation:

Area of the original square flower bed = x

Side length of the new square flower bed = 5 feet

Area of the new square flower bed = (x+7)

5^2 =(x+7)  (area of a square = side2)

5=√ x+7

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Is the circumference more or less then 33 centimeters?
Zinaida [17]
The circumference is greater than 33 centimeters, it stands somewhere around 11 π.
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3 years ago
3 10 in . = 7 8 mi . what is the unit rate
Sav [38]

Answer: (3/10) in = (7/8) mi

1 in = (7/8) mi ÷ (3/10)

      = 7/8 * (10/3) = 70/24

1 in = (70/24) mi

It means every 1 inch on the map drawing represents (70/24) miles ≈ 2.917 miles in reality.  

Hope this helps :)

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3 years ago
A color printer prints 18 pages in 8 minutes.<br>How many minutes does it take per page?​
Sav [38]

Answer:

2.25 pages per minute

Step-by-step explanation:

Step 1:

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Step 2:

2.25

Answer:

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4 0
3 years ago
What is the solution to this equation?
vampirchik [111]

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5 0
3 years ago
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken
Leviafan [203]

Answer:

a. H0:μ1≥μ2

Ha:μ1<μ2

b. t=-3.076

c. Rejection region=[tcalculated<−1.717]

Reject H0

Step-by-step explanation:

a)

As the score for group 1 is lower than group 2,

Null hypothesis: H0:μ1≥μ2

Alternative hypothesis: H1:μ1<μ2

b) t test statistic for equal variances

t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}

t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}

t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]

t=-3.076

c. α=0.05, df=22

t(0.05,22)=-1.717

The rejection region is t calculated<t critical value

t<-1.717

We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.

7 0
4 years ago
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