The quadratic equation is given by:
y = 3x² + 10x - 8
The standard equation of a parabola is given by:
y = ax² + bx + c
Where a, b, c are constants
At point (4, 80):
80 = a(4)² + b(4) + c
16a + 4b + c = 80 (1)
At point (-3, -11):
-11 = a(-3)² + b(-3) + c
9a - 3b + c = -11 (2)
At point (-1, -15):
-15 = a(-1)² + b(-1) + c
a - b + c = -15 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = 3, b = 10, c = -8
Therefore the quadratic equation becomes:
y = 3x² + 10x - 8
Find out more on quadratic equation at: brainly.com/question/1214333
Answer- (5x-1)(2x+1)
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Answer:
Easy
Step-by-step explanation:
To find the perimeter, add all the sides together.
12+16+20=48
To find the area, you multiply the sides that make the right angle of the triangle,
12×16=192
And divide it by two. This step is important as if you don't divide it by two, you will end up with the area of a square.
192÷2=96
Finito. Oh and don't forget to add units.
Cm for perimeter and Cm(squared) for area. :)
Answer:
Not a function
Step-by-step explanation:
Fails the vertical line test
Step-by-step explanation:
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