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IRISSAK [1]
3 years ago
13

If angle 5 is 120 degrees, what is the measure of angle 6? Why?

Mathematics
2 answers:
Sliva [168]3 years ago
4 0

Answer:the measure of angle 6 is 60 degrees.

Step-by-step explanation:

The two horizontal lines ate straight and parallel lines. It is established that the sum of the angles on a straight line is 180 degrees. Looking at the given figure, angle 5 and angle 6 are on a straight line. Therefore

Angle 5 + angle 6 = 180 degrees. Therefore,If angle 5 is 120 degrees,then

Angle 6 + 120 = 180

Angle 6 = 180 - 120 = 60 degrees.

Aleonysh [2.5K]3 years ago
3 0

Answer:because 5 and 6 have to equal 180 degrees so you subtract 180 - and angle 5 which gives you angle 6

Step-by-step explanation:

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(4-3)-6 = 1-6 = -5

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lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

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value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

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