All categories

3 years ago

Horace is a professional hair stylist.

Mathematics

2 answers:

Mice21 [21]3 years ago

7 0

Answer:

Step-by-step explanation:

0.75(5)+1.25(a)<7

3.75+1.25(a)<7

1.25(a)<3.25

a<2.6

therefore Horace can give 2.6 more haircuts but you can't do 2.6 of a haircut so with the remaining time he can do 2.

ANEK [815]3 years ago

7 0

Answer:

Horacio can cut the hair of 2 adults before the end of 7 hours

Step-by-step explanation:

To find the number of haircuts that Horacio can make to adults in the time he has left, you must first replace in inequality the number of haircuts he made to children and then resolve the inequality.

1. First replace the number of child haircuts on the inequality:

0.75C +1.25 A <7

0.75(5)+1.25A<7

3.75+1.25A<7

2. Solve for A:

1.25A<7-3.75

1.25A<3.25

A< $\frac{3.25}{1.25}$

A<2.6

Therefore Horacio can cut the hair of 2 adults before the end of 7 hours

You might be interested in

Subtract 42.5 – 7.32 = _____

denpristay [2]

Step-by-step explanation:

42.5 – 7.32 = __35.18___

5 0

3 years ago

Read 2 more answers

23+15=28<br> 46+52=66<br> 87+31=90<br> 72+32=45<br> 86+72=????

shtirl [24]

Answer:

Easy, all you have to do is add em all together 80+70=150 and 2+6=8 so 150+8=158

Step-by-step explanation:

6 0

3 years ago

Complete the data set with one value so that the mean of the data is 12.

sergey [27]

Answer:

the answer is 16

Step-by-step explanation:

12+15+15+16+6=64

now watch when i remove 16

12+15+15+6=48/4=12

so ur answer is 16

3 0

3 years ago

I have homework and i dont understand it its called "Solving Systems of Equations by Elimination." The problem im stuck on is&lt

lawyer [7]

You add the equations together making sure one of the variables disappears by making one negative and one positive. In this situation y would alrady disappear 8x+y=-16

7 0

4 years ago

Read 2 more answers

Let X equal the number of typos on a printed page with a mean of 4 typos per page.

timama [110]

Answer:

a) There is a 98.17% probability that a randomly selected page has at least one typo on it.

b) There is a 9.16% probability that a randomly selected page has at most one typo on it.

Step-by-step explanation:

Since we only have the mean, we can solve this problem by a Poisson distribution.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that $\mu = 4$

(a) What is the probability that a randomly selected page has at least one typo on it?

Thats is $P(X \geq 1)$ . Either a number is greater or equal than 1, or it is lesser. The sum of the probabilities must be decimal 1. So:

$P(X < 1) + P(X \geq 1) = 1$

$P(X \geq 1) = 1 - P(X < 1)$

In which

$P(X < 1) = P(X = 0)$ .

$P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183$

$P(X \geq 1) = 1 - P(X < 1) = 1 - 0.0183 = 0.9817$

There is a 98.17% probability that a randomly selected page has at least one typo on it.

(b) What is the probability that a randomly selected page has at most one typo on it?

This is $P = P(X = 0) + P(X = 1)$ . So:

$P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183$

$P(X = 1) = \frac{e^{-4}*4^{1}}{(1)!} = 0.0733$

$P = P(X = 0) + P(X = 1) = 0.0183 + 0.0733 = 0.0916$

There is a 9.16% probability that a randomly selected page has at most one typo on it.

3 0

3 years ago