Answer:
50/p increases from a small positive number to a big positive number.
Step-by-step explanation:
p is in the denominator. This means that p and the value of the expression 50/p are inverse proportional. So for a big value of p, 50/p has a small positive value. For a small value of p, 50/p has a high positive value.
what happens to the value of the expression 50/p as p decreases from a large positive number to a small positive number?
50/p increases from a small positive number to a big positive number.
For example
50/1000 = 0.05
50/1 = 50
Answer: 92
Step-by-step explanation: Subtract 257 & 162 to get your answer :)
<u>Option C is correct </u><u>(y + z = 6) ⋅ −3</u>
What is a linear equation in math?
- A linear equation only has one or two variables.
- No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
- When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.
As per the statement -
A student is trying to solve the system of two equations given below:
Equation P: y + z = 6 ....[1]
Equation Q: 3y + 4z = 1 ....[2]
Multiply the equation [1] by -3 to both sides we have;
-3 .( y + z = 6 ) ⇒ -3y -3z = -18..........(3)
Add equation [2] and [3] to eliminate the y-term;
z = -17
Therefore, the possible step used in eliminating the y-term is, (y + z = 6) ⋅ −3
Learn more about linear equation
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<u>The complete question is -</u>
A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 3y + 4z = 1 Which of these is a possible step used in eliminating the y-term?
(y + z = 6) ⋅ 4
(3y + 4z = 1) ⋅ 4
(y + z = 6) ⋅ −3
(3y + 4z = 1) ⋅ 3
2u = <-2, 4>
-v = <-3, 2>
3w = <0, -6>
I just multiplied each vector by its scalar, then added the components.
answer: <-5, 0>
<h3>
Answer: C) integers and rational numbers</h3>
Explanation:
The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} basically any number that does not have a decimal or fractional part to it. We can say that this set is composed of positive and negative whole numbers along with 0. So this is why -3 is in the set of integers.
The value -3 is not in the set of whole numbers because the set of whole numbers is {0, 1, 2, 3, 4, 5, 6, ...}, so this rules out choice D.
Choice B is also eliminated because -3 is a rational number. We can write -3 as a fraction of two integers, example: -3 = -3/1. Any rational number is not irrational, and vice versa.
Choice A is ruled out because it's not the most complete answer (though its technically true).