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3 years ago

Can Someone Help Me!!!!!!

Mathematics

2 answers:

Degger [83]3 years ago

4 0

The answer is D. 5 and 6
Hope it helped!

fenix001 [56]3 years ago

4 0

2 and 3/4 you multiply 2 and 4 and add 3. 11/4 The next fraction you multiply 1 and 4 and add 3. 7/14 Put your two answers on top of two seperate /4 add the answers. You will get in the end 18/4 but... you can divide and you get 4/5. Rate me thank me make me braileist answer thank you.

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Suppose you have ordered one medium onion ring and one 16oz chocolate shake from Burger King. The onion rings have 19 grams of f

dsp73

Part A:

23 + 13x ≤ 81

Part B:

23 + 13x ≤ 81

-23 -23

13x ≤ 58

/13 /13

x ≤ 4.46

Part C:

This means that you can have 4 cheeseburgers while keeping the fat under 81 grams.

5 0

3 years ago

Aiden and Haisem are going to eat the same amount of hamburgers and fries, but from different restaurants. Aiden goes to Burger

Paha777 [63]

Answer:

the burgers be 3 and fries be 2

Step-by-step explanation:

The computation is shown below:

Let us assume burgers be x

And, the fries be y

Now according to the questiojn

1.25x + 0.50y = $4.75

1.50x + 0.99y = $6.48

Now multiply by 1.2 in the first equation

1.50x + 0.6y = $5.70

1.50x + 0.99y = $6.48

-0.39y = -0.78

y = 2

Now put the value of y in any of the above equation

1.25x + 0.50(2) = $4.75

x = 3

Hence, the burgers be 3 and fries be 2

6 0

3 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago

"For which value of c does Limit of f (x) as x approaches c not exist?"

Damm [24]

The limit does not exist at the jump discontinuity at x = -2.

From the left, the green-ish curve approaches 4; from the right, the orange curve approaches 6. These one-sided limits are not equal, so the two-sided limit does not exist.

7 0

3 years ago

Challenge A bag contains pennies, nickels dimes, and quarters. There are 50 coins in all of the

vova2212 [387]

Answer:

The bag contains $5.14

Step-by-step explanation:

18% of 50 = (.18)(50) = 9 pennies

40% of 50 = (.40)(50) = 20 dimes

2 more nickels than pennies = 9 + 2 = 11 nickels

40 coins so far, so 50 - 40 = 10 quarters

Total value:

9 x ($0.01) = $0.09 for pennies

20 x ($0.10) = $2.00 for dimes

11 x ($0.05) = $0.55 for nickels

10 x ($0.25) = $2.50 for quarters

Grand total value = $5.14

7 0

3 years ago