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bixtya [17]
3 years ago
8

Factor f(x) = 4x^2 − 5x − 21

Mathematics
1 answer:
jeka943 years ago
4 0

Answer:

x = -7/4, 3

Step-by-step explanation:

Use quadratic formula

You might be interested in
Solve for x<br> X ²-5x=2(leave answer in a surd form)
Lubov Fominskaja [6]
Hello,

x²-5x-2=0
Δ=5²+4*2=33
==>x= (5-√33)/2 or x=(5+√33)/2


7 0
3 years ago
Which linear equation has a greater slope?<br> y = 2x + 1<br> Or<br> y = -1x + 4
Dafna11 [192]
Linear functions have the general form y=mx+b, where m is the slope. The first function has a slope of 2, while the second one has a slope of -1, so y=2x+1 has a greater slope.
5 0
3 years ago
Need answers ASAP
a_sh-v [17]
We know, Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 18³
v = 4.186 * 5832
v = 24,416.64 cm³

Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 12³
v = 4.186 * 1728
v = 7234.56 cm³

Difference = 24,416.64 - 7234.56 = 17182.08

In short, Your Answer would be: 17182.08 cm³

Hope this helps!
6 0
3 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
3 years ago
If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.
solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

WX=\sqrt{(-3-(-10))^2+(-1-4)^2}

WX=\sqrt{(-3+10)^2+(-5)^2}

WX=\sqrt{(7)^2+(-5)^2}

WX=\sqrt49+25}

WX=\sqrt{74}

Similarly,

XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}

WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}

Now,

WX=WY

So, triangle is an isosceles triangles.

and,

WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2

WX^2+WY^2=74+74

WX^2+WY^2=148

WX^2+WY^2=(2\sqrt{37})^2

WX^2+WY^2=WY^2

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0
2 years ago
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