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Aneli [31]
3 years ago
14

Which brand of gourmet pickles should Darryl purchase?

Mathematics
1 answer:
alexdok [17]3 years ago
6 0

Answer:

D

i hate edgunity just like you

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How many sq. ft. are in an acre?
Ainat [17]
43560 sq. ft
Answer till 20 characters 
8 0
3 years ago
Read 2 more answers
A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po
Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call h the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is h - 49.

The wire length d is 14 ft longer than height h, hence

d= h+14.

Thus we get a right triangle with hypotenuse d= y+14, perpendicular  h, and base h-49; therefore, the Pythagorean theorem gives

(h-49)^2+h^2 = (h+14)^2

which upon expanding we get:

h^2-98h+2401 = h^2+28h+196

further simplification gives

h^2-126h+2205=0,

which is a quadratic equation with solutions

h =21ft\\h = 105ft.

Since the first solution h =21ft will give the triangle base length of 21ft-49ft = -28ft which is negative; therefore, we disregard it and pick the solution h = 105ft.

Hence, the height of the pole is 105ft.

3 0
3 years ago
PLS HELP ASAP ILL GIVE BRAINLKEST PLS THANKS
allochka39001 [22]

Answer:

y = 3x

Step-by-step explanation:

Let's select two points from the given graph.

(1,3) (3,9)

Now, let's use slope formula to find the slope.

m = y2-y1/x2-x1

= 9-3/3-1

= 6/2

= 3

Let's substitute/plug this value into the slope-intercept form.

y = 3x + b

We can see that the y-intercept is 0, from the graph.

b = 0

Therefore,

y = 3x

4 0
3 years ago
Help me with this please
dedylja [7]

Answer:

{2}^{ - 14}  \times  {5}^{10}

4 0
3 years ago
Two telephone calls come into a switchboard at random times in a fixed one-hour period. Assume that the calls are made independe
svp [43]

Answer:

0.25

Step-by-step explanation:

From the given information:

Since the times are uniform distributed over the one hour period (0,1):

Then;

f_1(y_1) = 1

f_2(y_2) = 1

So, Y_1 and Y_2 are independent; then:

f(y_1|y_2) = f_1(y_1)f_2(y_2)  \\ \\ = 1(1) = 1

P(Y_1\le 0.5 Y_2 \le 0.5) = \int ^{0.5}_{0} \int ^{0.5}_{0} f(y_1,y_2) dy_{2}dy_{1}

\implies  \int ^{0.5}_{0} \int ^{0.5}_{0} (1)  dy_{2}dy_{1}

= \dfrac{1}{4}

= 0.25

3 0
3 years ago
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