Please help me! Will give brainlst :)
2 answers:
Answer:
12. 6.4
13. 20
Step-by-step explanation:
Mathematics: <u>Define and explain.</u>
This is a right triangle, so the Pythagorean Theorem applies.
The Pythagorean Theorem states that the sum of the squared side lengths of a right triangle must equal the hypotenuse when squared.
The legs of a triangle are the sides that form the right angle.
The hypotenuse is the longest side; the hypotenuse is always diagonal from the small square indicating a right angle.
Mathematics: <u>Solve.</u>
In the first triangle, the missing side length is the hypotenuse.
**41 IS NOT A PERFECT SQUARE. THEREFORE, I MUST ROUND THE SQUARE ROOT TO THE NEAREST TENTH.**
≈
Hence, the hypotenuse, c, is equal to 6.4.
In this second triangle, we are solving the find one of the legs.
Hence, one of the legs, b, is equal to 20.
Mathematics: <u>Conclude.</u>
12) The missing side is equal to 6.4 when rounded to the nearest tenth.
13) The missing side is equal to 20.
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i ) 3(2x - 3) = 4(2x + 4)
ii )2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)
2. 3x /4 - 7 /4 = 5x + 12
cancel 4 from both sides
3. x +7 - 8x/3 = 17/6 - 5x/8
put x = 4
L.H.S. = R.H.S.
<h2>--------------------</h2>4. Let 3 consecutive integers : x , x+1 , x+2
As per the question : 2x + 3(x+1) + 4(x+2) = 56
9x + 11 = 56
Transpose 11 to RHS
9x = 45
Divide both sides by 9
x = 5 ,
x + 1 = 5 + 1 = 6
x + 2 = 5 + 2 = 7
Numbers are 5 , 6 and 7 .
<h2>-----------------------</h2>5. Let the age of Jane’s younger sister is x.
Age of Jane will be x + 6
As per the question, after 10 years the sum of their ages will be 50.
After 10 years,
age of Jane = x + 16
age of her younger sister = x + 10
Therefore,
x + 16 + x +10 = 50
2x + 26 = 50
2x = 24
x = 12
Thus, the present age of Jane’s younger sister is 12 years.
And of Jane’s is 12 + 6 = 18 years.
<h2>---------------------</h2>6. Let the breadth of rectangular swimming pool be x metres.
Then, its length = (2x + 2) metres.
We know that the Perimeter of a rectangle
= 2(Length + Breadth)
= 2(2x + 2 + x) = 6x + 4
According to the given condition, we have
6x + 4 = 154
6x = 154 − 4
6x = 150
[Dividing both sides by 6]
x = 25
Thus, breadth = 25 m and
length = 25 × 2 + 2 = 52 m .
<h2>---------------------</h2>7. Let the digit in ten's .
Place be x and the digit in the one's place be y.
x − y = 5 ⟶ (i)
Two digit number = 10x + y
Two digit after reversing the digits = 10y + x
According to question ,
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 ⟶ (ii)
On adding (i) and (ii),
2x = 14
x = 7
Putting the value of x in equation (i)
x − y = 5
y = 2
Number = 10x + y
=72 .
<h2>-----------------------</h2>8. Let the speed of the steamer in still water be x km/h.
Then , the speed downstream = (x+2) km/h
and the speed upstream = (x−2) km/h
Given , distance covered in 4 hours downstream = distance covered in 5 hours upstream
4(x + 2) = 5(x − 2)
4x + 8 = 5x − 10
4x − 5x = − 10 − 8
[Transposing 5x to LHS and 8 to RHS]
−x = −18 or x = 18 km/h .
<h2>-----------------------</h2>9. Let the number of notes of different denomination be x.
∴ Numbers of Rs 100 notes , 50 notes and Rs 10 notes will be 2x , 3x and 5x respectively.
Amount of 100 Rs notes ⇒Rs 100 × 2x = 200x
Amount of 50 Rs notes ⇒Rs 50 × 3x = 150x
Amount of 10 Rs notes ⇒Rs 10 × 5x = 50x
As per the question
Total amount = 400000
200x + 150x + 50x = 400000
400x = 400000 , x = 1000
No of Rs 100 notes = 2x = 2 × 1000 = 2000
No of Rs 50 notes = 3x = 3 × 1000 = 3000
No of Rs 10 notes = 5x = 5 × 1000 = 5000 .
<h2>------------------------</h2>10. Let the age of the man be x
Then age of his son becomes (x − 24)
2 years later from now,
Age of man will be = x + 2
and age of his son will be = (x − 24 + 2) = x − 22
According to question,
2(x − 22) = x + 2
i.e., 2x − 44 = x + 2
i.e., x = 46
Therefore ,
Present age of man = 46 years
And present age of his son = 46 − 24 = 22 years .
Answer:
35.71m/s²
Step-by-step explanation:
using the formula force(F)=mass(m)×acceleration(a)
a =
F=15.0N
m=0.42kg
a=?
a=15÷0.42
a=35.71m/s²