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slavikrds [6]
3 years ago
12

In the past you paid $800 per month to rent your apartment. You now pay $900 per month for your rent. What is the percent increa

se in your rent?
Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0
If we take 800 to be the 100%, and the difference is just 100 bucks, how much is 100 off of it in percentage?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
800&100\\
100&p
\end{array}\implies \cfrac{800}{100}=\cfrac{100}{p}\implies p=\cfrac{100\cdot 100}{800}
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Rita = (11r + 32) 
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The slope of a line is . What is the slope of a line perpendicular to this line?
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Step-by-step explanation:

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Write a translation rule that maps point D(7,-3) onto point D'(2,5).
Sergio039 [100]
We are given D (7, -3) and D'(2, 5).

SAppy the transformation
D'(x,y) → D(x-5, y+8).
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6 0
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Read 2 more answers
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
Simplify: (3n2 +9+5n4 – 3n)+(-9n* - 7 -5n?)
Alona [7]

Answer:

3n^2+9+5n^4+55n

Step-by-step explanation:

Steps

$\left(3n^2+9+5n^4-3n\right)+\left(-9n\left(-7\right)-5n\right)$

$\mathrm{Remove\:parentheses}:\quad\left(a\right)=a,\:-\left(-a\right)=a$

$=3n^2+9+5n^4-3n+9n\cdot\:7-5n$

$\mathrm{Add\:similar\:elements:}\:-3n-5n=-8n$

$=3n^2+9+5n^4-8n+9\cdot\:7n$

$\mathrm{Multiply\:the\:numbers:}\:9\cdot\:7=63$

$=3n^2+9+5n^4-8n+63n$

$\mathrm{Add\:similar\:elements:}\:-8n+63n=55n$

$=3n^2+9+5n^4+55n$

7 0
3 years ago
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