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2 years ago

What is the product? (-3s+2t)(4s-t)

Mathematics

2 answers:

Step2247 [10]2 years ago

7 0

Answer:

−12s2+11st−2t2

Step-by-step explanation:

Hope this helps!

pashok25 [27]2 years ago

6 0

Answer:

-12s - 2t

Step-by-step explanation:

First simplify the like terms.

-3s * 4s = -12s

(-12s + 2t)(-t)

Simplify the like terms again.

2t * (-t) = -2t

-12s - 2t.

12s + 2t. (You can get this by multiplying the equation by -1)

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3 years ago

The first three steps of completing the square to solve the quadratic equation x^2 +4x-6=0, are shown below

GarryVolchara [31]

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3 years ago

Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN

sashaice [31]

Answer:

The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

and (x2 , y2) are $x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}$

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ $x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}$

∵ $y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}$

∴ The coordinates of the midpoint are $(-2\frac{1}{2},4\frac{1}{2})$

* The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

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3 years ago

What is the product? (-3s+2t)(4s-t)​

What is the product? (-3s+2t)(4s-t)