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icang [17]
3 years ago
8

a leaf hangs from a branch 12 feet in the air. it falls to the ground at a rate of 0.25 feet per second. which graph could repre

sent the leafs height in feet as a function of time, in seconds, after leaving the branch

Mathematics
1 answer:
Kipish [7]3 years ago
7 0
For this case we have an equation of the form:
 h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0

 Where,
 h0: initial height
 v0: initial speed
 a: acceleration
 Substituting values we have:
 h (t) = (1/2) * (- 32) * (t ^ 2) + 0.25 * t + 12

 Rewriting we have:
 h (t) = -16t ^ 2 + 0.25 * t + 12

 Note: see attached image
 Answer:
 
h (t) = -16t ^ 2 + 0.25 * t + 12

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(½) (6x + 3) = 7 – (3x + 1)
erastovalidia [21]

\tt Step-by-step~explanation:

To solve for x, we have to remember to isolate the variable.

\tt Step~1:

For 1/2, we can make that 0.5, since their values are equivalent. Our equation:

\tt (0.5)(6x+3)=7-(3x+1)

Let's distribute the 0.5 first.

\tt 0.5*6x=3x\\0.5*3=1.5

\tt Step~2:

Now, let's simplify the right side of the equation. We have to distribute the negative to 3x and 1.

\tt -1*3x=-3x\\-1*1=-1

Then, we simplify the entire expression.

\tt 7-3x-1=-3x+6

\tt Step~3:

Our equation now:

\tt 3x+1.5=-3x+6

Let's add 3x to the right and 3x to the left to simplify the -3x on the right side of the equation.

\tt 3x(+3x)+1.5=-3x (3x)+6\\6x+1.5=6

\tt Step~4:

Let's do the same thing we did in Step 3 to 1.5. Subtract 1.5 on both sides of the equation.

\tt 6x+1.5(-1.5)=6(-1.5)\\6x=4.5

\tt Step~5:

Finally, we divide both sides by 6 to isolate x.

\tt \frac{6x}{6} =x\\\frac{4.5}{6}= 0.75~or~\frac{3}{4}

\large\boxed{\tt Our~final~answer:~x=0.75~(or~\frac{3}{4})}

8 0
3 years ago
HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid
Harlamova29_29 [7]

Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

\angle BDA\cong \angle BDC ( right angles )

BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

\triangle ADB\cong \triangle CDB

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.




7 0
3 years ago
Read 2 more answers
If 2 sides of a triangle are 6 and 16, what is the range of the possible lengths of the third side?
Leno4ka [110]

Answer:

between 10 and 22

Step-by-step explanation:

A side of a triangle must measure between the difference of the lengths of the other two sides and the sum of the lengths of the other two sides.

Difference: 16 - 6 = 10

Sum: 6 + 16 = 22

Answer: between 10 and 22

6 0
3 years ago
How do I write 5/3x+y=8 in standard form
aivan3 [116]

Answer:

5x+3y+24

Step-by-step explanation:

5 0
3 years ago
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May I know the answer of number 1 pls quick
tino4ka555 [31]

n=9 would be your answer. Hope I helped

5 0
3 years ago
Read 2 more answers
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