Answer:
24
Step-by-step explanation:
So, Dersan's path is a right triangle. You have to find the last side. You can use the triples or 6^2+8^2=c^2 but I'll use a triple.
3,4,5.
The last side is 10.
6+8+10=24
hope this helped!
Answer: 7/8
Step-by-step explanation:
5+2+1 =8
5+2=7
7/8
Answer:
Here is the answer...hope it helps
Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.
We know that this is a parabola, as the equation is denoted by the x^2 term.
We can see that the symmetry is seen at the point -0.5, therefore making the axis of symmetry the vertical line -0.5.
The vertex is found in quadrant three. In other words, it will shift by a negative value both horizontally and vertically. The vertex is therefore (-0.5, -0.5).
We can verify this in the equations by using the formula (-b/2a) to find the vertex. The only quadratic equation that satisfies this is -2x^2 + 2x -1.
To sum it up, the answers are:
-2x^2 + 2x - 1.
AoS: x = -0.5
Vertex: (-0.5, -0.5).
